thus
( f is_less_than g iff for x being Element of X
for y being Element of Y holds f . (x,y) <= g . (x,y) )
verumproof
hereby ( ( for x being Element of X
for y being Element of Y holds f . (x,y) <= g . (x,y) ) implies f is_less_than g )
assume A1:
f is_less_than g
;
for x being Element of X
for y being Element of Y holds f . (x,y) <= g . (x,y)thus
for
x being
Element of
X for
y being
Element of
Y holds
f . (
x,
y)
<= g . (
x,
y)
verumproof
let x be
Element of
X;
for y being Element of Y holds f . (x,y) <= g . (x,y)let y be
Element of
Y;
f . (x,y) <= g . (x,y)
(
dom f = [:X,Y:] &
[x,y] in [:X,Y:] )
by FUNCT_2:def 1;
hence
f . (
x,
y)
<= g . (
x,
y)
by A1, FUZZY_1:def 1;
verum
end;
end;
assume A2:
for
x being
Element of
X for
y being
Element of
Y holds
f . (
x,
y)
<= g . (
x,
y)
;
f is_less_than g
A3:
for
c being
set st
c in dom f holds
f . c <= g . c
dom g = [:X,Y:]
by FUNCT_2:def 1;
hence
f is_less_than g
by A3, FUZZY_1:def 1;
verum
end;