let X be set ; for A, B, C being SetSequence of X st ( for n being Element of NAT holds C . n = (A . n) \/ (B . n) ) holds
lim_sup C = (lim_sup A) \/ (lim_sup B)
let A, B, C be SetSequence of X; ( ( for n being Element of NAT holds C . n = (A . n) \/ (B . n) ) implies lim_sup C = (lim_sup A) \/ (lim_sup B) )
assume A1:
for n being Element of NAT holds C . n = (A . n) \/ (B . n)
; lim_sup C = (lim_sup A) \/ (lim_sup B)
thus
lim_sup C c= (lim_sup A) \/ (lim_sup B)
XBOOLE_0:def 10 (lim_sup A) \/ (lim_sup B) c= lim_sup Cproof
let x be
set ;
TARSKI:def 3 ( not x in lim_sup C or x in (lim_sup A) \/ (lim_sup B) )
assume A2:
x in lim_sup C
;
x in (lim_sup A) \/ (lim_sup B)
( for
n being
Element of
NAT ex
k being
Element of
NAT st
x in A . (n + k) or for
n being
Element of
NAT ex
k being
Element of
NAT st
x in B . (n + k) )
proof
given n1 being
Element of
NAT such that A3:
for
k being
Element of
NAT holds not
x in A . (n1 + k)
;
for n being Element of NAT ex k being Element of NAT st x in B . (n + k)
given n2 being
Element of
NAT such that A4:
for
k being
Element of
NAT holds not
x in B . (n2 + k)
;
contradiction
set n =
max (
n1,
n2);
consider g being
Nat such that A5:
max (
n1,
n2)
= n1 + g
by NAT_1:10, XXREAL_0:25;
consider h being
Nat such that A6:
max (
n1,
n2)
= n2 + h
by NAT_1:10, XXREAL_0:25;
reconsider g =
g,
h =
h as
Element of
NAT by ORDINAL1:def 12;
consider k being
Element of
NAT such that A7:
x in C . ((max (n1,n2)) + k)
by A2, Th8;
A8:
x in (A . ((max (n1,n2)) + k)) \/ (B . ((max (n1,n2)) + k))
by A1, A7;
end;
then
(
x in lim_sup A or
x in lim_sup B )
by Th8;
hence
x in (lim_sup A) \/ (lim_sup B)
by XBOOLE_0:def 3;
verum
end;
thus
(lim_sup A) \/ (lim_sup B) c= lim_sup C
verum