let f be Polynomial of F_Complex; (f *') *' = f
set g = (f *') *' ;
A1:
now let k9 be
set ;
( k9 in dom ((f *') *') implies ((f *') *') . k9 = f . k9 )assume
k9 in dom ((f *') *')
;
((f *') *') . k9 = f . k9then reconsider k =
k9 as
Element of
NAT ;
((f *') *') . k =
((power F_Complex) . ((- (1_ F_Complex)),k)) * (((f *') . k) *')
by Def9
.=
((power F_Complex) . ((- (1_ F_Complex)),k)) * ((((power F_Complex) . ((- (1_ F_Complex)),k)) * ((f . k) *')) *')
by Def9
.=
((power F_Complex) . ((- (1_ F_Complex)),k)) * ((((power F_Complex) . ((- (1_ F_Complex)),k)) *') * (((f . k) *') *'))
by COMPLFLD:54
.=
(((power F_Complex) . ((- (1_ F_Complex)),k)) * (((power F_Complex) . ((- (1_ F_Complex)),k)) *')) * (f . k)
.=
(((power F_Complex) . ((- (1_ F_Complex)),k)) * ((power F_Complex) . (((- (1_ F_Complex)) *'),k))) * (f . k)
by Th5
.=
(((power F_Complex) . ((- (1_ F_Complex)),k)) * ((power F_Complex) . ((- (1_ F_Complex)),k))) * (f . k)
by Lm2, Lm3
.=
((power F_Complex) . ((- (1_ F_Complex)),(k + k))) * (f . k)
by Th3
.=
((power F_Complex) . ((- (1_ F_Complex)),(2 * k))) * (f . k)
.=
(1_ F_Complex) * (f . k)
by Th4
;
hence
((f *') *') . k9 = f . k9
by VECTSP_1:def 8;
verum end;
dom ((f *') *') =
NAT
by FUNCT_2:def 1
.=
dom f
by FUNCT_2:def 1
;
hence
(f *') *' = f
by A1, FUNCT_1:2; verum