let x, X be set ; :: thesis: for g, f being Function st g c= f & x in X & X /\ (dom f) c= dom g holds
f . x = g . x

let g, f be Function; :: thesis: ( g c= f & x in X & X /\ (dom f) c= dom g implies f . x = g . x )
assume that
Z1: g c= f and
Z2: x in X and
Z3: X /\ (dom f) c= dom g ; :: thesis: f . x = g . x
per cases ( x in dom g or not x in dom g ) ;
suppose x in dom g ; :: thesis: f . x = g . x
hence f . x = g . x by Z1, Th8; :: thesis: verum
end;
suppose S: not x in dom g ; :: thesis: f . x = g . x
end;
end;