let A, B be set ; for f, g being Function st dom f = dom g & dom f c= A \/ B & f | B = g | B holds
f,g equal_outside A
let f, g be Function; ( dom f = dom g & dom f c= A \/ B & f | B = g | B implies f,g equal_outside A )
assume that
A1:
dom f = dom g
and
A2:
dom f c= A \/ B
; ( not f | B = g | B or f,g equal_outside A )
assume
f | B = g | B
; f,g equal_outside A
hence
f | ((dom f) \ A) = g | ((dom g) \ A)
by A1, A2, RELAT_1:153, XBOOLE_1:43; FUNCT_7:def 2 verum