let L be Lattice; for p being Element of L st L is C_Lattice & L is modular holds
latt (L,(.p.>) is C_Lattice
let p be Element of L; ( L is C_Lattice & L is modular implies latt (L,(.p.>) is C_Lattice )
assume that
A1:
L is C_Lattice
and
A2:
L is modular
; latt (L,(.p.>) is C_Lattice
reconsider K = latt (L,(.p.>) as bounded Lattice by A1, Th83;
K is complemented
proof
let b9 be
Element of
K;
LATTICES:def 19 ex b1 being Element of the carrier of K st b1 is_a_complement_of b9
reconsider b =
b9 as
Element of
L by Th69;
consider a being
Element of
L such that A3:
a is_a_complement_of b
by A1, LATTICES:def 19;
A4:
a "\/" b = Top L
by A3, LATTICES:def 18;
A5:
H1(
K)
= (.p.>
by Th73;
then A6:
b [= p
by Th29;
p "/\" a [= p
by LATTICES:6;
then reconsider a9 =
p "/\" a as
Element of
K by A5, Th29;
take
a9
;
a9 is_a_complement_of b9
thus a9 "\/" b9 =
(p "/\" a) "\/" b
by Th74
.=
(b "\/" a) "/\" p
by A2, A6, LATTICES:def 12
.=
p
by A1, A4, LATTICES:17
.=
Top K
by Th81
;
LATTICES:def 18 ( b9 "\/" a9 = Top K & a9 "/\" b9 = Bottom K & b9 "/\" a9 = Bottom K )
hence
b9 "\/" a9 = Top K
;
( a9 "/\" b9 = Bottom K & b9 "/\" a9 = Bottom K )
A7:
a "/\" b = Bottom L
by A3, LATTICES:def 18;
thus a9 "/\" b9 =
(p "/\" a) "/\" b
by Th74
.=
p "/\" (Bottom L)
by A7, LATTICES:def 7
.=
Bottom L
by A1, LATTICES:15
.=
Bottom K
by A1, Th82
;
b9 "/\" a9 = Bottom K
hence
b9 "/\" a9 = Bottom K
;
verum
end;
hence
latt (L,(.p.>) is C_Lattice
; verum