let d be set ; for X1, X2, X3, X4 being non empty set
for x being Element of [:X1,X2,X3,X4:] holds
( d = x `4 iff for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4 )
let X1, X2, X3, X4 be non empty set ; for x being Element of [:X1,X2,X3,X4:] holds
( d = x `4 iff for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4 )
let x be Element of [:X1,X2,X3,X4:]; ( d = x `4 iff for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4 )
thus
( d = x `4 implies for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4 )
( ( for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4 ) implies d = x `4 )proof
A1:
x = [(x `1),(x `2),(x `3),(x `4)]
by MCART_1:56;
assume A2:
d = x `4
;
for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4
let x1 be
Element of
X1;
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4let x2 be
Element of
X2;
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4let x3 be
Element of
X3;
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4let x4 be
Element of
X4;
( x = [x1,x2,x3,x4] implies d = x4 )
assume
x = [x1,x2,x3,x4]
;
d = x4
hence
d = x4
by A2, A1, MCART_1:29;
verum
end;
thus
( ( for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
d = x4 ) implies d = x `4 )
by MCART_1:78; verum