let b be set ; for X1, X2, X3, X4 being non empty set
for x being Element of [:X1,X2,X3,X4:] holds
( b = x `2 iff for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2 )
let X1, X2, X3, X4 be non empty set ; for x being Element of [:X1,X2,X3,X4:] holds
( b = x `2 iff for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2 )
let x be Element of [:X1,X2,X3,X4:]; ( b = x `2 iff for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2 )
thus
( b = x `2 implies for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2 )
( ( for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2 ) implies b = x `2 )proof
A1:
x = [(x `1),(x `2),(x `3),(x `4)]
by MCART_1:56;
assume A2:
b = x `2
;
for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2
let x1 be
Element of
X1;
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2let x2 be
Element of
X2;
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2let x3 be
Element of
X3;
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2let x4 be
Element of
X4;
( x = [x1,x2,x3,x4] implies b = x2 )
assume
x = [x1,x2,x3,x4]
;
b = x2
hence
b = x2
by A2, A1, MCART_1:29;
verum
end;
thus
( ( for x1 being Element of X1
for x2 being Element of X2
for x3 being Element of X3
for x4 being Element of X4 st x = [x1,x2,x3,x4] holds
b = x2 ) implies b = x `2 )
by MCART_1:76; verum