let GX, GY be TopSpace; :: thesis: for F being Function of GX,GY st F is continuous & F .: ([#] GX) = [#] GY & GX is connected holds
GY is connected

let F be Function of GX,GY; :: thesis: ( F is continuous & F .: ([#] GX) = [#] GY & GX is connected implies GY is connected )
assume that
A1: F is continuous and
A2: F .: ([#] GX) = [#] GY and
A3: GX is connected ; :: thesis: GY is connected
assume not GY is connected ; :: thesis: contradiction
then consider A, B being Subset of GY such that
A4: [#] GY = A \/ B and
A5: A <> {} GY and
A6: B <> {} GY and
A7: A is closed and
A8: B is closed and
A9: A misses B by Th11;
A10: F " A is closed by A1, A7, PRE_TOPC:def 6;
A11: F " B is closed by A1, A8, PRE_TOPC:def 6;
A12: A /\ B = {} by A9, XBOOLE_0:def 7;
(F " A) /\ (F " B) = F " (A /\ B) by FUNCT_1:68
.= {} by A12, RELAT_1:136 ;
then A13: F " A misses F " B by XBOOLE_0:def 7;
A14: not the carrier of GY is empty by A5;
then A15: [#] GX = F " the carrier of GY by FUNCT_2:40
.= (F " A) \/ (F " B) by A4, RELAT_1:140 ;
A16: rng F = F .: the carrier of GX by A14, FUNCT_2:37;
then A17: F " B <> {} GX by A2, A6, RELAT_1:139;
F " A <> {} GX by A2, A5, A16, RELAT_1:139;
hence contradiction by A3, A15, A13, A10, A11, A17, Th11; :: thesis: verum