let H be ZF-formula; for M being non empty set
for v being Function of VAR,M st M,v |= All ((x. 3),(Ex ((x. 0),(All ((x. 4),(H <=> ((x. 4) '=' (x. 0)))))))) & not x. 4 in Free H holds
for m being Element of M holds (def_func' (H,v)) .: m = {}
let M be non empty set ; for v being Function of VAR,M st M,v |= All ((x. 3),(Ex ((x. 0),(All ((x. 4),(H <=> ((x. 4) '=' (x. 0)))))))) & not x. 4 in Free H holds
for m being Element of M holds (def_func' (H,v)) .: m = {}
let v be Function of VAR,M; ( M,v |= All ((x. 3),(Ex ((x. 0),(All ((x. 4),(H <=> ((x. 4) '=' (x. 0)))))))) & not x. 4 in Free H implies for m being Element of M holds (def_func' (H,v)) .: m = {} )
consider m3 being Element of M;
assume that
A1:
M,v |= All ((x. 3),(Ex ((x. 0),(All ((x. 4),(H <=> ((x. 4) '=' (x. 0))))))))
and
A2:
not x. 4 in Free H
; for m being Element of M holds (def_func' (H,v)) .: m = {}
M,v / ((x. 3),m3) |= Ex ((x. 0),(All ((x. 4),(H <=> ((x. 4) '=' (x. 0))))))
by A1, ZF_LANG1:80;
then consider m0 being Element of M such that
A3:
M,(v / ((x. 3),m3)) / ((x. 0),m0) |= All ((x. 4),(H <=> ((x. 4) '=' (x. 0))))
by ZF_LANG1:82;
let m be Element of M; (def_func' (H,v)) .: m = {}
consider u being Element of (def_func' (H,v)) .: m;
assume
(def_func' (H,v)) .: m <> {}
; contradiction
then consider u1 being set such that
A4:
u1 in dom (def_func' (H,v))
and
A5:
u1 in m
and
u = (def_func' (H,v)) . u1
by FUNCT_1:def 12;
set f = (v / ((x. 3),m3)) / ((x. 0),m0);
reconsider u1 = u1 as Element of M by A4;
A6:
now let m4 be
Element of
M;
( M,(v / ((x. 3),m3)) / ((x. 0),m0) |= H iff m4 = m0 )
M,
((v / ((x. 3),m3)) / ((x. 0),m0)) / (
(x. 4),
m4)
|= H <=> ((x. 4) '=' (x. 0))
by A3, ZF_LANG1:80;
then
(
M,
((v / ((x. 3),m3)) / ((x. 0),m0)) / (
(x. 4),
m4)
|= H iff
M,
((v / ((x. 3),m3)) / ((x. 0),m0)) / (
(x. 4),
m4)
|= (x. 4) '=' (x. 0) )
by ZF_MODEL:19;
then A7:
(
M,
(v / ((x. 3),m3)) / (
(x. 0),
m0)
|= H iff
(((v / ((x. 3),m3)) / ((x. 0),m0)) / ((x. 4),m4)) . (x. 4) = (((v / ((x. 3),m3)) / ((x. 0),m0)) / ((x. 4),m4)) . (x. 0) )
by A2, ZFMODEL2:10, ZF_MODEL:12;
(
(((v / ((x. 3),m3)) / ((x. 0),m0)) / ((x. 4),m4)) . (x. 4) = m4 &
((v / ((x. 3),m3)) / ((x. 0),m0)) . (x. 0) = m0 )
by FUNCT_7:130;
hence
(
M,
(v / ((x. 3),m3)) / (
(x. 0),
m0)
|= H iff
m4 = m0 )
by A7, FUNCT_7:34, ZF_LANG1:86;
verum end;
then
M,(v / ((x. 3),m3)) / ((x. 0),m0) |= H
;
then
( u1 = m0 & m = m0 )
by A6;
hence
contradiction
by A5; verum