let M be non empty set ; ( ( for X being set st X in M holds
X <> {} ) implies ex Choice being Function st
( dom Choice = M & ( for X being set st X in M holds
Choice . X in X ) ) )
assume A1:
for X being set st X in M holds
X <> {}
; ex Choice being Function st
( dom Choice = M & ( for X being set st X in M holds
Choice . X in X ) )
consider R being Relation such that
A2:
R well_orders union M
by Th26;
defpred S1[ set , set ] means ( $2 in $1 & ( for z being set st z in $1 holds
[$2,z] in R ) );
A3:
R is_connected_in union M
by A2, WELLORD1:def 5;
A4:
R is_reflexive_in union M
by A2, WELLORD1:def 5;
A5:
R is_well_founded_in union M
by A2, WELLORD1:def 5;
A6:
for x being set st x in M holds
ex y being set st S1[x,y]
proof
let x be
set ;
( x in M implies ex y being set st S1[x,y] )
assume A7:
x in M
;
ex y being set st S1[x,y]
then A8:
x c= union M
by ZFMISC_1:92;
x <> {}
by A1, A7;
then consider y being
set such that A9:
y in x
and A10:
R -Seg y misses x
by A5, A8, WELLORD1:def 3;
take
y
;
S1[x,y]
thus
y in x
by A9;
for z being set st z in x holds
[y,z] in R
let z be
set ;
( z in x implies [y,z] in R )
assume A11:
z in x
;
[y,z] in R
(R -Seg y) /\ x = {}
by A10, XBOOLE_0:def 7;
then A12:
not
z in R -Seg y
by A11, XBOOLE_0:def 4;
( not
y <> z or
[y,z] in R or
[z,y] in R )
by A3, A8, A9, A11, RELAT_2:def 6;
hence
[y,z] in R
by A4, A8, A11, A12, RELAT_2:def 1, WELLORD1:def 1;
verum
end;
A13:
R is_antisymmetric_in union M
by A2, WELLORD1:def 5;
A14:
for x, y, z being set st x in M & S1[x,y] & S1[x,z] holds
y = z
proof
let x,
y,
z be
set ;
( x in M & S1[x,y] & S1[x,z] implies y = z )
assume A15:
x in M
;
( not S1[x,y] or not S1[x,z] or y = z )
assume that A16:
y in x
and A17:
for
u being
set st
u in x holds
[y,u] in R
;
( not S1[x,z] or y = z )
A18:
y in union M
by A15, A16, TARSKI:def 4;
assume that A19:
z in x
and A20:
for
u being
set st
u in x holds
[z,u] in R
;
y = z
A21:
z in union M
by A15, A19, TARSKI:def 4;
(
[y,z] in R &
[z,y] in R )
by A16, A17, A19, A20;
hence
y = z
by A13, A18, A21, RELAT_2:def 4;
verum
end;
consider f being Function such that
A22:
( dom f = M & ( for x being set st x in M holds
S1[x,f . x] ) )
from FUNCT_1:sch 2(A14, A6);
take
f
; ( dom f = M & ( for X being set st X in M holds
f . X in X ) )
thus
( dom f = M & ( for X being set st X in M holds
f . X in X ) )
by A22; verum