let f be s.c.c. FinSequence of (TOP-REAL 2); for n being Element of NAT st n < len f holds
f | n is s.n.c.
let n be Element of NAT ; ( n < len f implies f | n is s.n.c. )
assume A1:
n < len f
; f | n is s.n.c.
let i, j be Nat; TOPREAL1:def 9 ( j <= i + 1 or LSeg ((f | n),i) misses LSeg ((f | n),j) )
assume A2:
i + 1 < j
; LSeg ((f | n),i) misses LSeg ((f | n),j)
A3:
j in NAT
by ORDINAL1:def 13;
A4:
i in NAT
by ORDINAL1:def 13;
A5:
len (f | n) <= n
by FINSEQ_5:19;
per cases
( n < j + 1 or len (f | n) < j + 1 or ( j + 1 <= n & j + 1 <= len (f | n) ) )
;
suppose that A6:
j + 1
<= n
and A7:
j + 1
<= len (f | n)
;
LSeg ((f | n),i) misses LSeg ((f | n),j)
j + 1
< len f
by A1, A6, XXREAL_0:2;
then A8:
LSeg (
f,
i)
misses LSeg (
f,
j)
by A2, A4, A3, GOBOARD5:def 4;
j <= j + 1
by NAT_1:11;
then A9:
i + 1
<= j + 1
by A2, XXREAL_0:2;
LSeg (
f,
j)
= LSeg (
(f | n),
j)
by A7, SPPOL_2:3;
hence
LSeg (
(f | n),
i)
misses LSeg (
(f | n),
j)
by A7, A8, A9, SPPOL_2:3, XXREAL_0:2;
verum end; end;