let S1, S2 be Element of QC-Sub-WFF ; :: thesis: ( S1 `2 = S2 `2 implies Sub_the_left_argument_of (Sub_& (S1,S2)) = S1 )
assume A1: S1 `2 = S2 `2 ; :: thesis: Sub_the_left_argument_of (Sub_& (S1,S2)) = S1
then Sub_& (S1,S2) is Sub_conjunctive by Th13;
hence Sub_the_left_argument_of (Sub_& (S1,S2)) = S1 by A1, Def31; :: thesis: verum