let SAS be Semi_Affine_Space; for a, b, c being Element of SAS st congr a,b,c,c holds
a = b
let a, b, c be Element of SAS; ( congr a,b,c,c implies a = b )
assume
congr a,b,c,c
; a = b
then
( ( a = b & c = c ) or ex p, q being Element of SAS st
( parallelogram p,q,a,b & parallelogram p,q,c,c ) )
by Def4;
hence
a = b
by Th54; verum