let X1, X2, X3, X4 be set ; ( X1 <> {} & X2 <> {} & X3 <> {} & X4 <> {} implies for x being Element of [:X1,X2,X3,X4:] holds
( x `1 = ((x `1) `1) `1 & x `2 = ((x `1) `1) `2 & x `3 = (x `1) `2 & x `4 = x `2 ) )
assume A1:
( X1 <> {} & X2 <> {} & X3 <> {} & X4 <> {} )
; for x being Element of [:X1,X2,X3,X4:] holds
( x `1 = ((x `1) `1) `1 & x `2 = ((x `1) `1) `2 & x `3 = (x `1) `2 & x `4 = x `2 )
let x be Element of [:X1,X2,X3,X4:]; ( x `1 = ((x `1) `1) `1 & x `2 = ((x `1) `1) `2 & x `3 = (x `1) `2 & x `4 = x `2 )
thus x `1 =
[(x `1),(x `2)] `1
by Def1
.=
([(x `1),(x `2),(x `3)] `1) `1
by Def1
.=
(([(x `1),(x `2),(x `3),(x `4)] `1) `1) `1
by Def1
.=
((x `1) `1) `1
by A1, Th60
; ( x `2 = ((x `1) `1) `2 & x `3 = (x `1) `2 & x `4 = x `2 )
thus x `2 =
[(x `1),(x `2)] `2
by Def2
.=
([(x `1),(x `2),(x `3)] `1) `2
by Def1
.=
(([(x `1),(x `2),(x `3),(x `4)] `1) `1) `2
by Def1
.=
((x `1) `1) `2
by A1, Th60
; ( x `3 = (x `1) `2 & x `4 = x `2 )
thus x `3 =
[(x `1),(x `2),(x `3)] `2
by Def2
.=
([(x `1),(x `2),(x `3),(x `4)] `1) `2
by Def1
.=
(x `1) `2
by A1, Th60
; x `4 = x `2
thus x `4 =
[(x `1),(x `2),(x `3),(x `4)] `2
by Def2
.=
x `2
by A1, Th60
; verum