let n be Nat; for K being Field
for M1, M2 being Matrix of n,K holds (M1 + M2) @ = (M1 @) + (M2 @)
let K be Field; for M1, M2 being Matrix of n,K holds (M1 + M2) @ = (M1 @) + (M2 @)
let M1, M2 be Matrix of n,K; (M1 + M2) @ = (M1 @) + (M2 @)
for i, j being Nat st [i,j] in Indices ((M1 + M2) @) holds
((M1 + M2) @) * (i,j) = ((M1 @) + (M2 @)) * (i,j)
proof
let i,
j be
Nat;
( [i,j] in Indices ((M1 + M2) @) implies ((M1 + M2) @) * (i,j) = ((M1 @) + (M2 @)) * (i,j) )
assume
[i,j] in Indices ((M1 + M2) @)
;
((M1 + M2) @) * (i,j) = ((M1 @) + (M2 @)) * (i,j)
then A1:
[i,j] in [:(Seg n),(Seg n):]
by MATRIX_1:25;
then A2:
[i,j] in Indices (M1 @)
by MATRIX_1:25;
(
i in Seg n &
j in Seg n )
by A1, ZFMISC_1:106;
then A3:
[j,i] in [:(Seg n),(Seg n):]
by ZFMISC_1:106;
then A4:
[j,i] in Indices M1
by MATRIX_1:25;
A5:
[j,i] in Indices M2
by A3, MATRIX_1:25;
[j,i] in Indices (M1 + M2)
by A3, MATRIX_1:25;
then ((M1 + M2) @) * (
i,
j) =
(M1 + M2) * (
j,
i)
by MATRIX_1:def 7
.=
(M1 * (j,i)) + (M2 * (j,i))
by A4, MATRIX_3:def 3
.=
((M1 @) * (i,j)) + (M2 * (j,i))
by A4, MATRIX_1:def 7
.=
((M1 @) * (i,j)) + ((M2 @) * (i,j))
by A5, MATRIX_1:def 7
.=
((M1 @) + (M2 @)) * (
i,
j)
by A2, MATRIX_3:def 3
;
hence
((M1 + M2) @) * (
i,
j)
= ((M1 @) + (M2 @)) * (
i,
j)
;
verum
end;
hence
(M1 + M2) @ = (M1 @) + (M2 @)
by MATRIX_1:28; verum