let f be FinSequence of (TOP-REAL 2); ( f is being_S-Seq implies for p being Point of (TOP-REAL 2) st p in L~ f & f . 1 in L~ (L_Cut (f,p)) holds
f . 1 = p )
assume A1:
f is being_S-Seq
; for p being Point of (TOP-REAL 2) st p in L~ f & f . 1 in L~ (L_Cut (f,p)) holds
f . 1 = p
then A2:
len f >= 2
by TOPREAL1:def 10;
A3:
len f in dom f
by A1, FINSEQ_5:6;
1 in dom f
by A1, FINSEQ_5:6;
then A4:
f /. 1 = f . 1
by PARTFUN1:def 8;
let p be Point of (TOP-REAL 2); ( p in L~ f & f . 1 in L~ (L_Cut (f,p)) implies f . 1 = p )
assume that
A5:
p in L~ f
and
A6:
f . 1 in L~ (L_Cut (f,p))
and
A7:
f . 1 <> p
; contradiction
set g = mid (f,((Index (p,f)) + 1),(len f));
A8:
not f . 1 in L~ (mid (f,((Index (p,f)) + 1),(len f)))
by A1, A5, Th9;
then
p <> f . ((Index (p,f)) + 1)
by A6, JORDAN3:def 4;
then A9:
L_Cut (f,p) = <*p*> ^ (mid (f,((Index (p,f)) + 1),(len f)))
by JORDAN3:def 4;
per cases
( mid (f,((Index (p,f)) + 1),(len f)) is empty or not mid (f,((Index (p,f)) + 1),(len f)) is empty )
;
suppose
not
mid (
f,
((Index (p,f)) + 1),
(len f)) is
empty
;
contradictionthen
L~ (L_Cut (f,p)) = (LSeg (p,((mid (f,((Index (p,f)) + 1),(len f))) /. 1))) \/ (L~ (mid (f,((Index (p,f)) + 1),(len f))))
by A9, SPPOL_2:20;
then A10:
f . 1
in LSeg (
p,
((mid (f,((Index (p,f)) + 1),(len f))) /. 1))
by A6, A8, XBOOLE_0:def 3;
A11:
1
+ 1
<= len f
by A1, TOPREAL1:def 10;
then A12:
2
in dom f
by FINSEQ_3:27;
consider i being
Element of
NAT such that A13:
1
<= i
and A14:
i + 1
<= len (<*p*> ^ (mid (f,((Index (p,f)) + 1),(len f))))
and A15:
f /. 1
in LSeg (
(<*p*> ^ (mid (f,((Index (p,f)) + 1),(len f)))),
i)
by A6, A4, A9, SPPOL_2:13;
LSeg (
(<*p*> ^ (mid (f,((Index (p,f)) + 1),(len f)))),
i)
c= LSeg (
f,
(((Index (p,f)) + i) -' 1))
by A5, A13, A14, JORDAN3:49;
then A16:
((Index (p,f)) + i) -' 1
= 1
by A1, A2, A15, JORDAN5B:33;
A17:
1
<= Index (
p,
f)
by A5, JORDAN3:41;
then
1
+ 1
<= (Index (p,f)) + i
by A13, XREAL_1:9;
then A18:
(Index (p,f)) + i = 1
+ 1
by A16, XREAL_1:237, XXREAL_0:2;
then
Index (
p,
f)
= 1
by A13, A17, Th10;
then
p in LSeg (
f,1)
by A5, JORDAN3:42;
then A19:
p in LSeg (
(f /. 1),
(f /. (1 + 1)))
by A11, TOPREAL1:def 5;
i = 1
by A13, A17, A18, Th10;
then
(mid (f,((Index (p,f)) + 1),(len f))) /. 1
= f /. (1 + 1)
by A3, A18, A12, SPRECT_2:12;
hence
contradiction
by A7, A4, A10, A19, SPRECT_3:16;
verum end; end;