let a be Real; for A being closed-interval Subset of REAL
for g, f1, f2, f being PartFunc of REAL,REAL
for Z being open Subset of REAL st A c= Z & g = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2))) & f1 . x = a ^2 & g . x > 0 ) ) & Z c= dom ((#R (1 / 2)) * g) & Z = dom f & f | A is continuous holds
integral (f,A) = ((- ((#R (1 / 2)) * g)) . (upper_bound A)) - ((- ((#R (1 / 2)) * g)) . (lower_bound A))
let A be closed-interval Subset of REAL; for g, f1, f2, f being PartFunc of REAL,REAL
for Z being open Subset of REAL st A c= Z & g = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2))) & f1 . x = a ^2 & g . x > 0 ) ) & Z c= dom ((#R (1 / 2)) * g) & Z = dom f & f | A is continuous holds
integral (f,A) = ((- ((#R (1 / 2)) * g)) . (upper_bound A)) - ((- ((#R (1 / 2)) * g)) . (lower_bound A))
let g, f1, f2, f be PartFunc of REAL,REAL; for Z being open Subset of REAL st A c= Z & g = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2))) & f1 . x = a ^2 & g . x > 0 ) ) & Z c= dom ((#R (1 / 2)) * g) & Z = dom f & f | A is continuous holds
integral (f,A) = ((- ((#R (1 / 2)) * g)) . (upper_bound A)) - ((- ((#R (1 / 2)) * g)) . (lower_bound A))
let Z be open Subset of REAL; ( A c= Z & g = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2))) & f1 . x = a ^2 & g . x > 0 ) ) & Z c= dom ((#R (1 / 2)) * g) & Z = dom f & f | A is continuous implies integral (f,A) = ((- ((#R (1 / 2)) * g)) . (upper_bound A)) - ((- ((#R (1 / 2)) * g)) . (lower_bound A)) )
assume A1:
( A c= Z & g = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2))) & f1 . x = a ^2 & g . x > 0 ) ) & Z c= dom ((#R (1 / 2)) * g) & Z = dom f & f | A is continuous )
; integral (f,A) = ((- ((#R (1 / 2)) * g)) . (upper_bound A)) - ((- ((#R (1 / 2)) * g)) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
for x being Real st x in Z holds
( f1 . x = a ^2 & g . x > 0 )
by A1;
A4:
Z c= dom (- ((#R (1 / 2)) * g))
by A1, VALUED_1:8;
for y being set st y in Z holds
y in dom g
by A1, FUNCT_1:21;
then A6:
Z c= dom (f1 + ((- 1) (#) f2))
by A1, TARSKI:def 3;
A7:
(#R (1 / 2)) * g is_differentiable_on Z
by A1, A3, FDIFF_7:27;
then A8:
(- 1) (#) ((#R (1 / 2)) * g) is_differentiable_on Z
by A4, FDIFF_1:28, X;
A9:
( f2 = #Z 2 & ( for x being Real st x in Z holds
f1 . x = (a ^2) + (0 * x) ) )
by A1;
then A10:
( g is_differentiable_on Z & ( for x being Real st x in Z holds
(g `| Z) . x = 0 + ((2 * (- 1)) * x) ) )
by A1, A6, FDIFF_4:12, X;
A11:
for x being Real st x in Z holds
((- ((#R (1 / 2)) * g)) `| Z) . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2)))
proof
let x be
Real;
( x in Z implies ((- ((#R (1 / 2)) * g)) `| Z) . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2))) )
assume A12:
x in Z
;
((- ((#R (1 / 2)) * g)) `| Z) . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2)))
then A13:
x in dom (f1 - f2)
by A1, FUNCT_1:21;
A14:
g is_differentiable_in x
by A10, A12, FDIFF_1:16;
A15:
(f1 - f2) . x =
(f1 . x) - (f2 . x)
by A13, VALUED_1:13
.=
(a ^2) - (f2 . x)
by A1, A12
.=
(a ^2) - (x #Z 2)
by A1, TAYLOR_1:def 1
;
then A16:
(
g . x = (a ^2) - (x #Z 2) &
g . x > 0 )
by A1, A12;
A17:
(#R (1 / 2)) * g is_differentiable_in x
by A7, A12, FDIFF_1:16;
((- ((#R (1 / 2)) * g)) `| Z) . x =
diff (
(- ((#R (1 / 2)) * g)),
x)
by A8, A12, FDIFF_1:def 8
.=
(- 1) * (diff (((#R (1 / 2)) * g),x))
by A17, FDIFF_1:23, X
.=
(- 1) * (((1 / 2) * ((g . x) #R ((1 / 2) - 1))) * (diff (g,x)))
by A14, A16, TAYLOR_1:22
.=
(- 1) * (((1 / 2) * ((g . x) #R ((1 / 2) - 1))) * ((g `| Z) . x))
by A10, A12, FDIFF_1:def 8
.=
(- 1) * (((1 / 2) * ((g . x) #R ((1 / 2) - 1))) * (0 + ((2 * (- 1)) * x)))
by A1, A6, A9, FDIFF_4:12, X, A12
.=
x * (((a ^2) - (x #Z 2)) #R (- (1 / 2)))
by A1, A15
;
hence
((- ((#R (1 / 2)) * g)) `| Z) . x = x * (((a ^2) - (x #Z 2)) #R (- (1 / 2)))
;
verum
end;
A18:
for x being Real st x in dom ((- ((#R (1 / 2)) * g)) `| Z) holds
((- ((#R (1 / 2)) * g)) `| Z) . x = f . x
dom ((- ((#R (1 / 2)) * g)) `| Z) = dom f
by A1, A8, FDIFF_1:def 8;
then
(- ((#R (1 / 2)) * g)) `| Z = f
by A18, PARTFUN1:34;
hence
integral (f,A) = ((- ((#R (1 / 2)) * g)) . (upper_bound A)) - ((- ((#R (1 / 2)) * g)) . (lower_bound A))
by A1, A2, A8, INTEGRA5:13; verum