set mc = multcomplex ;
consider f being FinSequence of COMPLEX such that
A9:
f = F
and
A10:
Product F = multcomplex $$ f
by RVSUM_1:def 14;
set g = [#] (f,(the_unity_wrt multcomplex));
defpred S1[ Element of NAT ] means multcomplex $$ ((finSeg F),([#] (f,(the_unity_wrt multcomplex)))) is integer ;
A11:
for k being Element of NAT st S1[k] holds
S1[k + 1]
proof
let k be
Element of
NAT ;
( S1[k] implies S1[k + 1] )
A12:
([#] (f,(the_unity_wrt multcomplex))) . (k + 1) is
integer
assume
S1[
k]
;
S1[k + 1]
then reconsider a =
([#] (f,(the_unity_wrt multcomplex))) . (k + 1),
b =
multcomplex $$ (
(finSeg k),
([#] (f,(the_unity_wrt multcomplex)))) as
integer number by A12;
not
k + 1
in Seg k
by FINSEQ_3:9;
then multcomplex $$ (
((finSeg k) \/ {.(k + 1).}),
([#] (f,(the_unity_wrt multcomplex)))) =
multcomplex . (
(multcomplex $$ ((finSeg k),([#] (f,(the_unity_wrt multcomplex))))),
(([#] (f,(the_unity_wrt multcomplex))) . (k + 1)))
by SETWOP_2:4
.=
b * a
by BINOP_2:def 5
;
hence
S1[
k + 1]
by FINSEQ_1:11;
verum
end;
Seg 0 = {}. NAT
;
then A13:
S1[ 0 ]
by BINOP_2:6, SETWISEO:40;
A14:
for n being Element of NAT holds S1[n]
from NAT_1:sch 1(A13, A11);
consider n being Nat such that
A15:
dom f = Seg n
by FINSEQ_1:def 2;
A16:
multcomplex $$ f = multcomplex $$ ((findom f),([#] (f,(the_unity_wrt multcomplex))))
by SETWOP_2:def 2;
n in NAT
by ORDINAL1:def 13;
hence
Product F is integer
by A10, A16, A15, A14; verum