let i, j, n, k be Element of NAT ; ADD_MOD ((ADD_MOD (i,j,n)),k,n) = ADD_MOD (i,(ADD_MOD (j,k,n)),n)
thus ADD_MOD ((ADD_MOD (i,j,n)),k,n) =
((i + j) + k) mod (2 to_power n)
by NAT_D:23
.=
(i + (j + k)) mod (2 to_power n)
.=
ADD_MOD (i,(ADD_MOD (j,k,n)),n)
by NAT_D:22
; verum