let G be Group; for A being non empty Subset of G
for N1, N2 being strict normal Subgroup of G ex N being strict normal Subgroup of G st
( the carrier of N = N1 * N2 & N ~ A c= ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1) )
let A be non empty Subset of G; for N1, N2 being strict normal Subgroup of G ex N being strict normal Subgroup of G st
( the carrier of N = N1 * N2 & N ~ A c= ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1) )
let N1, N2 be strict normal Subgroup of G; ex N being strict normal Subgroup of G st
( the carrier of N = N1 * N2 & N ~ A c= ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1) )
consider N being strict normal Subgroup of G such that
A1:
the carrier of N = N1 * N2
by Th8;
N ~ A c= ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1)
proof
let x be
set ;
TARSKI:def 3 ( not x in N ~ A or x in ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1) )
assume A2:
x in N ~ A
;
x in ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1)
then reconsider x =
x as
Element of
G ;
x * N meets A
by A2, Th14;
then consider x1 being
set such that A4:
(
x1 in x * N &
x1 in A )
by XBOOLE_0:3;
reconsider x1 =
x1 as
Element of
G by A4;
consider y being
Element of
G such that A5:
(
x1 = x * y &
y in N )
by A4, GROUP_2:125;
A6:
y in N1 * N2
by A1, A5, STRUCT_0:def 5;
then consider a,
b being
Element of
G such that A7:
(
y = a * b &
a in N1 &
b in N2 )
by Th6;
A8:
x1 = (x * a) * b
by A5, A7, GROUP_1:def 4;
a in carr N1
by A7, STRUCT_0:def 5;
then A9:
(x * a) * b in (x * N1) * b
by GROUP_8:15;
(x * N1) * b =
x * (N1 * b)
by GROUP_2:128
.=
x * (b * N1)
by GROUP_3:140
.=
(x * b) * N1
by GROUP_2:127
;
then
(x * b) * N1 meets A
by A4, A8, A9, XBOOLE_0:3;
then A10:
x * b in N1 ~ A
;
A11:
(x * b) * (b ") =
x * (b * (b "))
by GROUP_1:def 4
.=
x * (1_ G)
by GROUP_1:def 6
.=
x
by GROUP_1:def 5
;
b " in N2
by A7, GROUP_2:60;
then A12:
x in (N1 ~ A) * N2
by A10, A11, GROUP_2:114;
y in N2 * N1
by A6, GROUP_3:148;
then consider a,
b being
Element of
G such that A13:
(
y = a * b &
a in N2 &
b in N1 )
by Th6;
A14:
x1 = (x * a) * b
by A5, A13, GROUP_1:def 4;
a in carr N2
by A13, STRUCT_0:def 5;
then A15:
(x * a) * b in (x * N2) * b
by GROUP_8:15;
(x * N2) * b =
x * (N2 * b)
by GROUP_2:128
.=
x * (b * N2)
by GROUP_3:140
.=
(x * b) * N2
by GROUP_2:127
;
then
(x * b) * N2 meets A
by A4, A14, A15, XBOOLE_0:3;
then A16:
x * b in N2 ~ A
;
A17:
(x * b) * (b ") =
x * (b * (b "))
by GROUP_1:def 4
.=
x * (1_ G)
by GROUP_1:def 6
.=
x
by GROUP_1:def 5
;
b " in N1
by A13, GROUP_2:60;
then
x in (N2 ~ A) * N1
by A16, A17, GROUP_2:114;
hence
x in ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1)
by A12, XBOOLE_0:def 4;
verum
end;
hence
ex N being strict normal Subgroup of G st
( the carrier of N = N1 * N2 & N ~ A c= ((N1 ~ A) * N2) /\ ((N2 ~ A) * N1) )
by A1; verum