let Y, X be set ; ( Y <> {} implies rng (pr1 (X,Y)) = X )
consider y being Element of Y;
assume A1:
Y <> {}
; rng (pr1 (X,Y)) = X
A2:
X c= rng (pr1 (X,Y))
proof
let x be
set ;
TARSKI:def 3 ( not x in X or x in rng (pr1 (X,Y)) )
assume A3:
x in X
;
x in rng (pr1 (X,Y))
then
[x,y] in [:X,Y:]
by A1, ZFMISC_1:106;
then A4:
[x,y] in dom (pr1 (X,Y))
by Def5;
(pr1 (X,Y)) . (
x,
y)
= x
by A1, A3, Def5;
hence
x in rng (pr1 (X,Y))
by A4, FUNCT_1:def 5;
verum
end;
rng (pr1 (X,Y)) c= X
by Th59;
hence
rng (pr1 (X,Y)) = X
by A2, XBOOLE_0:def 10; verum