let n, m be natural number ; :: thesis: ( (idseq n) | (Seg m) = idseq m iff m <= n )
thus ( (idseq n) | (Seg m) = idseq m implies m <= n ) :: thesis: ( m <= n implies (idseq n) | (Seg m) = idseq m )
proof end;
assume m <= n ; :: thesis: (idseq n) | (Seg m) = idseq m
then ex j being Nat st n = m + j by NAT_1:10;
hence (idseq n) | (Seg m) = idseq m by Th56; :: thesis: verum