let n be Nat; for F, F2 being FinSequence of REAL n
for h being Permutation of (dom F) st F2 = F (*) h holds
Sum F2 = Sum F
let F, F2 be FinSequence of REAL n; for h being Permutation of (dom F) st F2 = F (*) h holds
Sum F2 = Sum F
let h be Permutation of (dom F); ( F2 = F (*) h implies Sum F2 = Sum F )
assume A1:
F2 = F (*) h
; Sum F2 = Sum F
per cases
( len F > 0 or len F <= 0 )
;
suppose A2:
len F > 0
;
Sum F2 = Sum Fthen A3:
0 + 1
<= len F
by NAT_1:13;
then A4:
1
in Seg (len F)
by FINSEQ_1:3;
then A5:
1
in dom F
by FINSEQ_1:def 3;
then A6:
dom h = dom F
by FUNCT_2:def 1;
then
rng h = dom h
by FUNCT_2:def 3;
then A7:
dom F2 = dom h
by A1, RELAT_1:46;
then A8:
Seg (len F2) = dom F
by A6, FINSEQ_1:def 3;
set gF =
accum F;
A9:
len F = len (accum F)
by Def11;
A11:
for
i being
Nat st 1
<= i &
i < len F holds
(accum F) . (i + 1) = ((accum F) /. i) + (F /. (i + 1))
by Def11;
defpred S1[
Nat]
means for
h2 being
Permutation of
(dom F) st $1
< len F & ( for
i being
Nat st $1
+ 1
< i &
i <= len F holds
h2 . i = i ) holds
(accum F) . ($1 + 1) = (accum (F (*) h2)) . ($1 + 1);
A13:
dom F = Seg (len F)
by FINSEQ_1:def 3;
1
in Seg (len F2)
by A5, A6, A7, FINSEQ_1:def 3;
then A14:
1
<= len F2
by FINSEQ_1:3;
A15:
(len F) -' 1
= (len F) - 1
by A3, XREAL_1:235;
then A16:
for
i being
Nat st
((len F) -' 1) + 1
< i &
i <= len F holds
h . i = i
;
A17:
dom F <> {}
by A4, FINSEQ_1:def 3;
A18:
for
k being
Nat st
S1[
k] holds
S1[
k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume A19:
S1[
k]
;
S1[k + 1]
for
h2 being
Permutation of
(dom F) st
k + 1
< len F & ( for
i being
Nat st
(k + 1) + 1
< i &
i <= len F holds
h2 . i = i ) holds
(accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1)
proof
A20:
1
<= k + 1
by NAT_1:11;
A21:
k + 1
< (k + 1) + 1
by XREAL_1:31;
let h2 be
Permutation of
(dom F);
( k + 1 < len F & ( for i being Nat st (k + 1) + 1 < i & i <= len F holds
h2 . i = i ) implies (accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1) )
assume that A22:
k + 1
< len F
and A23:
for
i being
Nat st
(k + 1) + 1
< i &
i <= len F holds
h2 . i = i
;
(accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1)
A24:
(k + 1) + 1
<= len F
by A22, NAT_1:13;
k < k + 1
by XREAL_1:31;
then A25:
k < len F
by A22, XXREAL_0:2;
A26:
1
< (k + 1) + 1
by XREAL_1:31;
then A27:
(k + 1) + 1
in Seg (len F)
by A24, FINSEQ_1:3;
then A28:
(k + 1) + 1
in dom F
by FINSEQ_1:def 3;
A29:
dom h2 = dom F
by A5, FUNCT_2:def 1;
then A30:
rng h2 = dom h2
by FUNCT_2:def 3;
then A31:
dom (F (*) h2) =
dom h2
by RELAT_1:46
.=
dom F
by A5, FUNCT_2:def 1
;
then A32:
Seg (len (F (*) h2)) = dom F
by FINSEQ_1:def 3;
then A33:
Seg (len (F (*) h2)) = Seg (len F)
by FINSEQ_1:def 3;
A34:
len (F (*) h2) = len F
by A32, FINSEQ_1:def 3;
h2 is
FinSequence
by A13, A29, FINSEQ_1:def 2;
then reconsider h2r =
h2 as
FinSequence of
NAT by A29, A30, FINSEQ_1:def 4;
dom h2 = Seg (len F)
by A2, A13, FUNCT_2:def 1;
then A35:
len h2r = len F
by FINSEQ_1:def 3;
consider x being
set such that A36:
x in dom h2
and A37:
(k + 1) + 1
= h2 . x
by A13, A29, A30, A27, FUNCT_1:def 5;
reconsider nx =
x as
Element of
NAT by A29, A36;
A38:
nx <= len F
by A13, A36, FINSEQ_1:3;
reconsider h2b =
Swap (
h2r,
nx,
((k + 1) + 1)) as
FinSequence of
NAT ;
A39:
rng h2b =
rng h2
by FINSEQ_7:24
.=
dom F
by FUNCT_2:def 3
;
A40:
len h2b = len h2r
by FINSEQ_7:20;
then
dom h2b = Seg (len h2r)
by FINSEQ_1:def 3;
then A41:
dom h2b =
dom h2
by FINSEQ_1:def 3
.=
dom F
by A17, FUNCT_2:def 1
;
then reconsider h2d =
h2b as
Function of
(dom F),
(dom F) by A39, FUNCT_2:3;
A42:
h2d is
one-to-one
by INT_5:39;
h2d is
onto
by A39, FUNCT_2:def 3;
then reconsider h4 =
h2d as
Permutation of
(dom F) by A42;
A43:
1
<= nx
by A13, A36, FINSEQ_1:3;
then A44:
h4 . nx = h2r . ((k + 1) + 1)
by A24, A26, A38, A35, Th11;
A45:
dom h4 = dom F
by A5, FUNCT_2:def 1;
rng h4 c= dom F
;
then A46:
dom (F (*) h4) =
dom h4
by RELAT_1:46
.=
dom F
by A5, FUNCT_2:def 1
;
then
Seg (len (F (*) h4)) = dom F
by FINSEQ_1:def 3;
then A47:
len (F (*) h4) = len F
by FINSEQ_1:def 3;
per cases
( nx <= k + 1 or nx > k + 1 )
;
suppose A48:
nx <= k + 1
;
(accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1)A49:
(k + 1) + 1
<= len h2r
by A22, A35, NAT_1:13;
A50:
nx <= len h2r
by A13, A36, A35, FINSEQ_1:3;
A51:
F . ((k + 1) + 1) = (F (*) h2) . nx
by A36, A37, FUNCT_1:23;
A52:
len (accum (F (*) h4)) = len (F (*) h4)
by Def11;
A53:
1
<= nx
by A13, A36, FINSEQ_1:3;
A54:
1
<= (k + 1) + 1
by NAT_1:11;
then A55:
h2b . ((k + 1) + 1) = (k + 1) + 1
by A37, A53, A50, A49, Th11;
A56:
for
i being
Nat st
k + 1
< i &
i <= len F holds
h4 . i = i
proof
let i be
Nat;
( k + 1 < i & i <= len F implies h4 . i = i )
assume that A57:
k + 1
< i
and A58:
i <= len F
;
h4 . i = i
A59:
(k + 1) + 1
<= i
by A57, NAT_1:13;
per cases
( (k + 1) + 1 < i or (k + 1) + 1 >= i )
;
suppose A60:
(k + 1) + 1
< i
;
h4 . i = i
1
<= k + 1
by NAT_1:11;
then A61:
1
< i
by A57, XXREAL_0:2;
then h4 . i =
h2b /. i
by A35, A40, A58, FINSEQ_4:24
.=
h2r /. i
by A35, A48, A57, A58, A60, A61, FINSEQ_7:32
.=
h2 . i
by A35, A58, A61, FINSEQ_4:24
.=
i
by A23, A58, A60
;
hence
h4 . i = i
;
verum end; end;
end; A62:
F /. ((k + 1) + 1) = F . ((k + 1) + 1)
by A24, A26, FINSEQ_4:24;
A63:
1
<= k + 1
by NAT_1:11;
A64:
len (accum (F (*) h2)) = len (F (*) h2)
by Def11;
A65:
nx < (k + 1) + 1
by A21, A48, XXREAL_0:2;
A66:
for
i4 being
Nat st 1
<= i4 &
i4 < nx holds
(accum (F (*) h2)) . i4 = (accum (F (*) h4)) . i4
proof
defpred S2[
Nat]
means ( 1
+ $1
< nx implies
(accum (F (*) h2)) . (1 + $1) = (accum (F (*) h4)) . (1 + $1) );
let i4 be
Nat;
( 1 <= i4 & i4 < nx implies (accum (F (*) h2)) . i4 = (accum (F (*) h4)) . i4 )
assume that A67:
1
<= i4
and A68:
i4 < nx
;
(accum (F (*) h2)) . i4 = (accum (F (*) h4)) . i4
A69: 1
+ (i4 -' 1) =
(i4 - 1) + 1
by A67, XREAL_1:235
.=
i4
;
A70:
for
k3 being
Nat st
S2[
k3] holds
S2[
k3 + 1]
proof
let k3 be
Nat;
( S2[k3] implies S2[k3 + 1] )
A71:
1
<= k3 + 1
by NAT_1:11;
assume A72:
S2[
k3]
;
S2[k3 + 1]
( 1
+ (k3 + 1) < nx implies
(accum (F (*) h2)) . (1 + (k3 + 1)) = (accum (F (*) h4)) . (1 + (k3 + 1)) )
proof
assume A73:
1
+ (k3 + 1) < nx
;
(accum (F (*) h2)) . (1 + (k3 + 1)) = (accum (F (*) h4)) . (1 + (k3 + 1))
then A74:
1
+ (k3 + 1) < len F
by A38, XXREAL_0:2;
then A75:
h2r /. ((k3 + 1) + 1) = h2r . ((k3 + 1) + 1)
by A35, FINSEQ_4:24, NAT_1:11;
A76:
(k3 + 1) + 1
< (k + 1) + 1
by A65, A73, XXREAL_0:2;
A77:
h2b /. ((k3 + 1) + 1) = h2b . ((k3 + 1) + 1)
by A35, A40, A74, FINSEQ_4:24, NAT_1:11;
1
<= 1
+ (k3 + 1)
by NAT_1:11;
then
(k3 + 1) + 1
in Seg (len F)
by A74, FINSEQ_1:3;
then A78:
(k3 + 1) + 1
in dom (F (*) h2)
by A31, FINSEQ_1:def 3;
then A79:
(F (*) h2) . ((k3 + 1) + 1) =
F . (h2 . ((k3 + 1) + 1))
by FUNCT_1:22
.=
F . (h4 . ((k3 + 1) + 1))
by A35, A73, A74, A76, A75, A77, FINSEQ_7:32, NAT_1:11
.=
(F (*) h4) . ((k3 + 1) + 1)
by A46, A31, A78, FUNCT_1:22
;
A80:
(F (*) h4) /. ((k3 + 1) + 1) = (F (*) h4) . ((k3 + 1) + 1)
by A47, A74, FINSEQ_4:24, NAT_1:11;
A81:
k3 + 1
< 1
+ (k3 + 1)
by XREAL_1:31;
then A82:
k3 + 1
< nx
by A73, XXREAL_0:2;
then A83:
k3 + 1
< len F
by A38, XXREAL_0:2;
k3 + 1
< len (F (*) h2)
by A38, A34, A82, XXREAL_0:2;
then A84:
(accum (F (*) h4)) /. (1 + k3) = (accum (F (*) h4)) . (1 + k3)
by A47, A34, A52, FINSEQ_4:24, NAT_1:11;
(accum (F (*) h2)) /. (1 + k3) = (accum (F (*) h2)) . (1 + k3)
by A34, A64, A83, FINSEQ_4:24, NAT_1:11;
then (accum (F (*) h2)) . (1 + (k3 + 1)) =
((accum (F (*) h4)) /. (k3 + 1)) + ((F (*) h2) /. ((k3 + 1) + 1))
by A34, A72, A71, A73, A81, A83, A84, Def11, XXREAL_0:2
.=
((accum (F (*) h4)) /. (k3 + 1)) + ((F (*) h4) /. ((k3 + 1) + 1))
by A34, A74, A79, A80, FINSEQ_4:24, NAT_1:11
;
hence
(accum (F (*) h2)) . (1 + (k3 + 1)) = (accum (F (*) h4)) . (1 + (k3 + 1))
by A47, A71, A83, Def11;
verum
end;
hence
S2[
k3 + 1]
;
verum
end;
0 < k + 1
;
then A85:
1
<> (k + 1) + 1
;
A86:
h2b /. 1
= h2b . 1
by A3, A35, A40, FINSEQ_4:24;
A87:
h2r /. 1
= h2r . 1
by A3, A35, FINSEQ_4:24;
(F (*) h2) . 1 =
F . (h2 . 1)
by A5, A31, FUNCT_1:22
.=
F . (h4 . 1)
by A3, A35, A67, A68, A85, A87, A86, FINSEQ_7:32
.=
(F (*) h4) . 1
by A5, A46, FUNCT_1:22
;
then (accum (F (*) h2)) . (1 + 0) =
(F (*) h4) . 1
by Def11
.=
(accum (F (*) h4)) . (1 + 0)
by Def11
;
then A88:
S2[
0 ]
;
for
k3 being
Nat holds
S2[
k3]
from NAT_1:sch 2(A88, A70);
hence
(accum (F (*) h2)) . i4 = (accum (F (*) h4)) . i4
by A68, A69;
verum
end; A89:
for
i being
Nat st
nx <= i &
i < (k + 1) + 1 holds
(accum (F (*) h2)) . i = (((accum (F (*) h4)) /. i) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
proof
defpred S2[
Nat]
means (
nx <= nx + $1 &
nx + $1
< (k + 1) + 1 implies
(accum (F (*) h2)) . (nx + $1) = (((accum (F (*) h4)) /. (nx + $1)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx) );
let i be
Nat;
( nx <= i & i < (k + 1) + 1 implies (accum (F (*) h2)) . i = (((accum (F (*) h4)) /. i) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx) )
assume that A90:
nx <= i
and A91:
i < (k + 1) + 1
;
(accum (F (*) h2)) . i = (((accum (F (*) h4)) /. i) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
A92:
len (accum (F (*) h4)) = len (F (*) h4)
by Def11;
A93:
len (accum (F (*) h2)) = len (F (*) h2)
by Def11;
A94:
for
k3 being
Nat st
S2[
k3] holds
S2[
k3 + 1]
proof
let k3 be
Nat;
( S2[k3] implies S2[k3 + 1] )
assume A95:
S2[
k3]
;
S2[k3 + 1]
(
nx <= nx + (k3 + 1) &
nx + (k3 + 1) < (k + 1) + 1 implies
(accum (F (*) h2)) . (nx + (k3 + 1)) = (((accum (F (*) h4)) /. (nx + (k3 + 1))) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx) )
proof
reconsider f3 =
(F (*) h2) /. ((nx + k3) + 1) as
Element of
REAL n ;
A96:
nx <= nx + k3
by NAT_1:11;
reconsider f2 =
(F (*) h2) /. ((k + 1) + 1) as
Element of
REAL n ;
A97:
nx + k3 < (nx + k3) + 1
by XREAL_1:31;
reconsider f4 =
(F (*) h2) /. nx as
Element of
REAL n ;
reconsider f1 =
(accum (F (*) h4)) /. (nx + k3) as
Element of
REAL n ;
assume that
nx <= nx + (k3 + 1)
and A98:
nx + (k3 + 1) < (k + 1) + 1
;
(accum (F (*) h2)) . (nx + (k3 + 1)) = (((accum (F (*) h4)) /. (nx + (k3 + 1))) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
A99:
nx + (k3 + 1) < len (accum (F (*) h4))
by A24, A47, A92, A98, XXREAL_0:2;
A100:
nx + k3 < (nx + k3) + 1
by XREAL_1:31;
then
nx + k3 < (k + 1) + 1
by A98, XXREAL_0:2;
then A101:
nx + k3 < len (F (*) h2)
by A35, A34, A49, XXREAL_0:2;
then A102:
(nx + k3) + 1
<= len (F (*) h2)
by NAT_1:13;
nx + k3 >= 0 + 1
by A43, NAT_1:13;
then A103:
1
< nx + (k3 + 1)
by A100, XXREAL_0:2;
then A104:
(F (*) h4) /. ((nx + k3) + 1) = (F (*) h4) . ((nx + k3) + 1)
by A47, A34, A102, FINSEQ_4:24;
(nx + k3) + 1
in Seg (len (F (*) h2))
by A103, A102, FINSEQ_1:3;
then A105:
(nx + k3) + 1
in dom (F (*) h2)
by FINSEQ_1:def 3;
then A106:
(F (*) h4) . ((nx + k3) + 1) =
F . (h4 . ((nx + k3) + 1))
by A46, A31, FUNCT_1:22
.=
F . (h2b /. ((nx + k3) + 1))
by A35, A40, A34, A103, A102, FINSEQ_4:24
.=
F . (h2r /. ((nx + k3) + 1))
by A35, A34, A98, A103, A102, A97, A96, FINSEQ_7:32
.=
F . (h2r . ((nx + k3) + 1))
by A35, A34, A103, A102, FINSEQ_4:24
.=
(F (*) h2) . ((nx + k3) + 1)
by A105, FUNCT_1:22
;
nx <= nx + k3
by NAT_1:11;
then A107:
1
<= nx + k3
by A53, XXREAL_0:2;
then (accum (F (*) h4)) . (nx + (k3 + 1)) =
((accum (F (*) h4)) /. (nx + k3)) + ((F (*) h4) /. ((nx + k3) + 1))
by A47, A34, A101, Def11
.=
((accum (F (*) h4)) /. (nx + k3)) + ((F (*) h2) /. ((nx + k3) + 1))
by A103, A102, A106, A104, FINSEQ_4:24
;
then A108:
(((accum (F (*) h4)) /. (nx + (k3 + 1))) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx) =
((f1 + f3) - f2) + f4
by A103, A99, FINSEQ_4:24
.=
((f1 - f2) + f3) + f4
by RFUNCT_1:19
.=
((f1 - f2) + f4) + f3
by RFUNCT_1:19
;
(accum (F (*) h2)) . (nx + (k3 + 1)) =
((accum (F (*) h2)) /. (nx + k3)) + ((F (*) h2) /. ((nx + k3) + 1))
by A107, A101, Def11
.=
((((accum (F (*) h4)) /. (nx + k3)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)) + ((F (*) h2) /. ((nx + k3) + 1))
by A93, A95, A98, A100, A107, A101, FINSEQ_4:24, NAT_1:11, XXREAL_0:2
;
hence
(accum (F (*) h2)) . (nx + (k3 + 1)) = (((accum (F (*) h4)) /. (nx + (k3 + 1))) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
by A108;
verum
end;
hence
S2[
k3 + 1]
;
verum
end;
now per cases
( 1 = nx or 1 < nx )
by A43, XXREAL_0:1;
case A109:
1
= nx
;
(accum (F (*) h2)) . (nx + 0) = (((accum (F (*) h4)) /. (nx + 0)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)A110:
n in NAT
by ORDINAL1:def 13;
(accum (F (*) h4)) /. (nx + 0) =
(accum (F (*) h4)) . 1
by A3, A47, A92, A109, FINSEQ_4:24
.=
(F (*) h4) . 1
by Def11
.=
F . (h2 . ((k + 1) + 1))
by A5, A45, A44, A109, FUNCT_1:23
.=
(F (*) h2) . ((k + 1) + 1)
by A29, A28, FUNCT_1:23
.=
(F (*) h2) /. ((k + 1) + 1)
by A24, A26, A34, FINSEQ_4:24
;
then A111:
(((accum (F (*) h4)) /. (nx + 0)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx) =
(0* n) + ((F (*) h2) /. nx)
by A110, EUCLIDLP:7
.=
(F (*) h2) /. nx
by EUCLID_4:1
;
(accum (F (*) h2)) . (nx + 0) =
(F (*) h2) . 1
by A109, Def11
.=
(F (*) h2) /. nx
by A38, A34, A109, FINSEQ_4:24
;
hence
(accum (F (*) h2)) . (nx + 0) = (((accum (F (*) h4)) /. (nx + 0)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
by A111;
verum end; case A112:
1
< nx
;
(accum (F (*) h2)) . (nx + 0) = (((accum (F (*) h4)) /. (nx + 0)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)A113:
(F (*) h4) /. nx =
(F (*) h4) . nx
by A43, A38, A47, FINSEQ_4:24
.=
F . (h2 . ((k + 1) + 1))
by A36, A45, A44, FUNCT_1:23
.=
(F (*) h2) . ((k + 1) + 1)
by A29, A28, FUNCT_1:23
.=
(F (*) h2) /. ((k + 1) + 1)
by A24, A26, A34, FINSEQ_4:24
;
A114:
nx -' 1
= nx - 1
by A112, XREAL_1:235;
then
nx -' 1
> 0
by A112, XREAL_1:52;
then A115:
nx -' 1
>= 0 + 1
by NAT_1:13;
nx < nx + 1
by XREAL_1:31;
then A116:
nx - 1
< (nx + 1) - 1
by XREAL_1:11;
then A117:
nx -' 1
< len (F (*) h2)
by A35, A34, A50, A114, XXREAL_0:2;
then A118:
(accum (F (*) h2)) /. (nx -' 1) = (accum (F (*) h2)) . (nx -' 1)
by A93, A115, FINSEQ_4:24;
(accum (F (*) h4)) . (nx + 0) =
((accum (F (*) h4)) /. (nx -' 1)) + ((F (*) h4) /. ((nx -' 1) + 1))
by A47, A34, A114, A115, A117, Def11
.=
((accum (F (*) h4)) /. (nx -' 1)) + ((F (*) h2) /. ((k + 1) + 1))
by A114, A113
;
then A119:
((accum (F (*) h4)) /. (nx + 0)) - ((F (*) h2) /. ((k + 1) + 1)) =
(((accum (F (*) h4)) /. (nx -' 1)) + ((F (*) h2) /. ((k + 1) + 1))) - ((F (*) h2) /. ((k + 1) + 1))
by A35, A47, A53, A50, A92, FINSEQ_4:24
.=
(accum (F (*) h4)) /. (nx -' 1)
by RVSUM_1:63
;
A120:
(accum (F (*) h4)) /. (nx -' 1) = (accum (F (*) h4)) . (nx -' 1)
by A47, A34, A92, A115, A117, FINSEQ_4:24;
(accum (F (*) h2)) . (nx + 0) =
((accum (F (*) h2)) /. (nx -' 1)) + ((F (*) h2) /. ((nx -' 1) + 1))
by A114, A115, A117, Def11
.=
((accum (F (*) h4)) /. (nx -' 1)) + ((F (*) h2) /. nx)
by A66, A114, A115, A116, A118, A120
;
hence
(accum (F (*) h2)) . (nx + 0) = (((accum (F (*) h4)) /. (nx + 0)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
by A119;
verum end; end; end;
then A121:
S2[
0 ]
;
A122:
for
k3 being
Nat holds
S2[
k3]
from NAT_1:sch 2(A121, A94);
A123:
i -' nx = i - nx
by A90, XREAL_1:235;
then
nx <= nx + (i -' nx)
by A90;
hence
(accum (F (*) h2)) . i = (((accum (F (*) h4)) /. i) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
by A91, A122, A123;
verum
end; A124:
(F (*) h2) /. nx = (F (*) h2) . nx
by A43, A38, A34, FINSEQ_4:24;
A125:
(k + 1) + 1
in dom h4
by A27, A41, FINSEQ_1:def 3;
A126:
(F (*) h4) /. ((k + 1) + 1) = (F (*) h4) . ((k + 1) + 1)
by A24, A26, A47, FINSEQ_4:24;
A127:
for
i being
Nat st
(k + 1) + 1
<= i &
i <= len F holds
(accum (F (*) h2)) . i = (accum (F (*) h4)) . i
proof
defpred S2[
Nat]
means (
((k + 1) + 1) + $1
<= len F implies
(accum (F (*) h2)) . (((k + 1) + 1) + $1) = (accum (F (*) h4)) . (((k + 1) + 1) + $1) );
let i be
Nat;
( (k + 1) + 1 <= i & i <= len F implies (accum (F (*) h2)) . i = (accum (F (*) h4)) . i )
assume that A128:
(k + 1) + 1
<= i
and A129:
i <= len F
;
(accum (F (*) h2)) . i = (accum (F (*) h4)) . i
A130:
for
k3 being
Nat st
S2[
k3] holds
S2[
k3 + 1]
proof
let k3 be
Nat;
( S2[k3] implies S2[k3 + 1] )
assume A131:
S2[
k3]
;
S2[k3 + 1]
(
((k + 1) + 1) + (k3 + 1) <= len F implies
(accum (F (*) h2)) . (((k + 1) + 1) + (k3 + 1)) = (accum (F (*) h4)) . (((k + 1) + 1) + (k3 + 1)) )
proof
A132:
(k + 1) + 1
<= ((k + 1) + 1) + k3
by NAT_1:11;
A133:
((k + 1) + 1) + k3 < (((k + 1) + 1) + k3) + 1
by XREAL_1:31;
then A134:
(k + 1) + 1
< (((k + 1) + 1) + k3) + 1
by A132, XXREAL_0:2;
assume A135:
((k + 1) + 1) + (k3 + 1) <= len F
;
(accum (F (*) h2)) . (((k + 1) + 1) + (k3 + 1)) = (accum (F (*) h4)) . (((k + 1) + 1) + (k3 + 1))
then A136:
(F (*) h4) /. ((((k + 1) + 1) + k3) + 1) = (F (*) h4) . ((((k + 1) + 1) + k3) + 1)
by A47, FINSEQ_4:24, NAT_1:11;
1
<= (((k + 1) + 1) + k3) + 1
by NAT_1:11;
then
(((k + 1) + 1) + k3) + 1
in Seg (len (F (*) h2))
by A33, A135, FINSEQ_1:3;
then A137:
(((k + 1) + 1) + k3) + 1
in dom (F (*) h2)
by FINSEQ_1:def 3;
then A138:
(F (*) h4) . ((((k + 1) + 1) + k3) + 1) =
F . (h4 . ((((k + 1) + 1) + k3) + 1))
by A46, A31, FUNCT_1:22
.=
F . (h2b /. ((((k + 1) + 1) + k3) + 1))
by A35, A40, A135, FINSEQ_4:24, NAT_1:11
.=
F . (h2r /. ((((k + 1) + 1) + k3) + 1))
by A35, A65, A135, A134, FINSEQ_7:32, NAT_1:11
.=
F . (h2r . ((((k + 1) + 1) + k3) + 1))
by A35, A135, FINSEQ_4:24, NAT_1:11
.=
(F (*) h2) . ((((k + 1) + 1) + k3) + 1)
by A137, FUNCT_1:22
;
1
<= (k + 1) + 1
by NAT_1:11;
then A139:
1
<= ((k + 1) + 1) + k3
by A132, XXREAL_0:2;
A140:
((k + 1) + 1) + k3 < len F
by A135, A133, XXREAL_0:2;
then A141:
(accum (F (*) h4)) /. (((k + 1) + 1) + k3) = (accum (F (*) h4)) . (((k + 1) + 1) + k3)
by A47, A52, A139, FINSEQ_4:24;
(accum (F (*) h2)) . (((k + 1) + 1) + (k3 + 1)) =
((accum (F (*) h2)) /. (((k + 1) + 1) + k3)) + ((F (*) h2) /. ((((k + 1) + 1) + k3) + 1))
by A34, A140, A139, Def11
.=
((accum (F (*) h4)) /. (((k + 1) + 1) + k3)) + ((F (*) h2) /. ((((k + 1) + 1) + k3) + 1))
by A34, A64, A131, A140, A139, A141, FINSEQ_4:24
.=
((accum (F (*) h4)) /. (((k + 1) + 1) + k3)) + ((F (*) h4) /. ((((k + 1) + 1) + k3) + 1))
by A34, A135, A138, A136, FINSEQ_4:24, NAT_1:11
;
hence
(accum (F (*) h2)) . (((k + 1) + 1) + (k3 + 1)) = (accum (F (*) h4)) . (((k + 1) + 1) + (k3 + 1))
by A47, A140, A139, Def11;
verum
end;
hence
S2[
k3 + 1]
;
verum
end;
A142:
len (accum (F (*) h2)) = len (F (*) h2)
by Def11;
A143:
(accum (F (*) h2)) . (k + 1) = (((accum (F (*) h4)) /. (k + 1)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)
by A21, A48, A89;
A144:
1
<= k + 1
by NAT_1:11;
k + 1
< len (F (*) h2)
by A22, A32, FINSEQ_1:def 3;
then (accum (F (*) h2)) . ((k + 1) + 1) =
((accum (F (*) h2)) /. (k + 1)) + ((F (*) h2) /. ((k + 1) + 1))
by A144, Def11
.=
((((accum (F (*) h4)) /. (k + 1)) - ((F (*) h2) /. ((k + 1) + 1))) + ((F (*) h2) /. nx)) + ((F (*) h2) /. ((k + 1) + 1))
by A22, A34, A142, A143, FINSEQ_4:24, NAT_1:11
.=
((accum (F (*) h4)) /. (k + 1)) + ((F (*) h2) /. nx)
by Th6
.=
((accum (F (*) h4)) /. (k + 1)) + ((F (*) h4) /. ((k + 1) + 1))
by A125, A55, A51, A126, A124, FUNCT_1:23
;
then A145:
S2[
0 ]
by A22, A20, A47, Def11;
A146:
for
k3 being
Nat holds
S2[
k3]
from NAT_1:sch 2(A145, A130);
((k + 1) + 1) + (i -' ((k + 1) + 1)) =
(i - ((k + 1) + 1)) + ((k + 1) + 1)
by A128, XREAL_1:235
.=
i
;
hence
(accum (F (*) h2)) . i = (accum (F (*) h4)) . i
by A129, A146;
verum
end; A147:
(accum F) /. (k + 1) = (accum F) . (k + 1)
by A9, A22, FINSEQ_4:24, NAT_1:11;
A148:
dom h4 = dom F
by A5, FUNCT_2:def 1;
rng h4 c= dom F
;
then A149:
dom (F (*) h4) = dom h4
by RELAT_1:46;
then
Seg (len (F (*) h4)) = dom h4
by FINSEQ_1:def 3;
then A150:
k + 1
< len (F (*) h4)
by A22, A148, FINSEQ_1:def 3;
Seg (len (F (*) h4)) = dom F
by A148, A149, FINSEQ_1:def 3;
then
len (F (*) h4) = len F
by FINSEQ_1:def 3;
then A151:
(F (*) h4) /. ((k + 1) + 1) = (F (*) h4) . ((k + 1) + 1)
by A24, A26, FINSEQ_4:24;
len (accum (F (*) h4)) = len (F (*) h4)
by Def11;
then A152:
(accum (F (*) h4)) /. (k + 1) = (accum (F (*) h4)) . (k + 1)
by A150, FINSEQ_4:24, NAT_1:11;
(accum F) . ((k + 1) + 1) =
((accum F) /. (k + 1)) + (F /. ((k + 1) + 1))
by A11, A22, NAT_1:11
.=
((accum (F (*) h4)) /. (k + 1)) + (F /. ((k + 1) + 1))
by A19, A25, A56, A152, A147
.=
((accum (F (*) h4)) /. (k + 1)) + ((F (*) h4) /. ((k + 1) + 1))
by A125, A55, A151, A62, FUNCT_1:23
.=
(accum (F (*) h4)) . ((k + 1) + 1)
by A63, A150, Def11
;
hence
(accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1)
by A24, A127;
verum end; suppose
nx > k + 1
;
(accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1)then A153:
(k + 1) + 1
<= nx
by NAT_1:13;
per cases
( (k + 1) + 1 = nx or (k + 1) + 1 < nx )
by A153, XXREAL_0:1;
suppose A154:
(k + 1) + 1
= nx
;
(accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1)A155:
for
i being
Nat st
k + 1
< i &
i <= len F holds
h2 . i = i
A159:
k + 1
< len (F (*) h2)
by A22, A32, FINSEQ_1:def 3;
len (accum (F (*) h2)) = len (F (*) h2)
by Def11;
then A160:
(accum (F (*) h2)) /. (k + 1) = (accum (F (*) h2)) . (k + 1)
by A22, A34, FINSEQ_4:24, NAT_1:11;
A161:
1
<= k + 1
by NAT_1:11;
A162:
F . ((k + 1) + 1) = (F (*) h2) . nx
by A36, A37, FUNCT_1:23;
A163:
(accum F) /. (k + 1) = (accum F) . (k + 1)
by A9, A22, FINSEQ_4:24, NAT_1:11;
A164:
F /. ((k + 1) + 1) = F . ((k + 1) + 1)
by A24, A26, FINSEQ_4:24;
(accum F) . ((k + 1) + 1) =
((accum F) /. (k + 1)) + (F /. ((k + 1) + 1))
by A11, A22, NAT_1:11
.=
((accum (F (*) h2)) /. (k + 1)) + (F /. ((k + 1) + 1))
by A19, A25, A155, A160, A163
.=
((accum (F (*) h2)) /. (k + 1)) + ((F (*) h2) /. ((k + 1) + 1))
by A24, A26, A34, A154, A164, A162, FINSEQ_4:24
.=
(accum (F (*) h2)) . ((k + 1) + 1)
by A161, A159, Def11
;
hence
(accum F) . ((k + 1) + 1) = (accum (F (*) h2)) . ((k + 1) + 1)
;
verum end; end; end; end;
end;
hence
S1[
k + 1]
;
verum
end;
for
h2 being
Permutation of
(dom F) st ( for
i being
Nat st
0 + 1
< i &
i <= len F holds
h2 . i = i ) holds
(accum F) . (0 + 1) = (accum (F (*) h2)) . (0 + 1)
proof
let h2 be
Permutation of
(dom F);
( ( for i being Nat st 0 + 1 < i & i <= len F holds
h2 . i = i ) implies (accum F) . (0 + 1) = (accum (F (*) h2)) . (0 + 1) )
A165:
rng h2 = dom F
by FUNCT_2:def 3;
A166:
dom h2 = dom F
by A5, FUNCT_2:def 1;
assume A167:
for
i being
Nat st
0 + 1
< i &
i <= len F holds
h2 . i = i
;
(accum F) . (0 + 1) = (accum (F (*) h2)) . (0 + 1)
A168:
now assume A169:
h2 . 1
<> 1
;
contradictionconsider x being
set such that A170:
x in dom h2
and A171:
h2 . x = 1
by A5, A165, FUNCT_1:def 5;
reconsider nx =
x as
Element of
NAT by A166, A170;
1
<= nx
by A13, A170, FINSEQ_1:3;
then
(
nx = 1 or ( 1
< nx &
nx <= len F ) )
by A13, A170, FINSEQ_1:3, XXREAL_0:1;
hence
contradiction
by A167, A169, A171;
verum end;
(accum (F (*) h2)) . 1 =
(F (*) h2) . 1
by Def11
.=
F . 1
by A5, A166, A168, FUNCT_1:23
;
hence
(accum F) . (0 + 1) = (accum (F (*) h2)) . (0 + 1)
by Def11;
verum
end; then A172:
S1[
0 ]
;
for
k being
Nat holds
S1[
k]
from NAT_1:sch 2(A172, A18);
then (accum F) . (len F) =
(accum (F (*) h)) . (len F)
by A15, A16, XREAL_1:46
.=
(accum F2) . (len F2)
by A1, A8, FINSEQ_1:def 3
.=
Sum F2
by A14, Def10
;
hence
Sum F2 = Sum F
by A2, Def10;
verum end; end;