defpred S1[ set , set ] means for g being Morphism of C st g = $1 holds
$2 = f * g;
set X = Hom (a,(dom f));
set Y = Hom (a,(cod f));
A1:
for x being set st x in Hom (a,(dom f)) holds
ex y being set st
( y in Hom (a,(cod f)) & S1[x,y] )
proof
let x be
set ;
( x in Hom (a,(dom f)) implies ex y being set st
( y in Hom (a,(cod f)) & S1[x,y] ) )
assume A2:
x in Hom (
a,
(dom f))
;
ex y being set st
( y in Hom (a,(cod f)) & S1[x,y] )
then reconsider g =
x as
Morphism of
a,
dom f by CAT_1:def 7;
take
f * g
;
( f * g in Hom (a,(cod f)) & S1[x,f * g] )
(
Hom (
(dom f),
(cod f))
<> {} &
f is
Morphism of
dom f,
cod f )
by CAT_1:18, CAT_1:22;
hence
(
f * g in Hom (
a,
(cod f)) &
S1[
x,
f * g] )
by A2, CAT_1:51;
verum
end;
consider h being Function such that
A3:
( dom h = Hom (a,(dom f)) & rng h c= Hom (a,(cod f)) )
and
A4:
for x being set st x in Hom (a,(dom f)) holds
S1[x,h . x]
from WELLORD2:sch 1(A1);
Hom ((dom f),(cod f)) <> {}
by CAT_1:19;
then
( Hom (a,(cod f)) = {} implies Hom (a,(dom f)) = {} )
by CAT_1:52;
then reconsider h = h as Function of (Hom (a,(dom f))),(Hom (a,(cod f))) by A3, FUNCT_2:def 1, RELSET_1:11;
take
h
; for g being Morphism of C st g in Hom (a,(dom f)) holds
h . g = f * g
thus
for g being Morphism of C st g in Hom (a,(dom f)) holds
h . g = f * g
by A4; verum