let m, n be Nat; ( 2 * (m + 1) <= n implies card (Domin_0 (n,(m + 1))) = (n choose (m + 1)) - (n choose m) )
set CH = Choose (n,(m + 1),1,0);
set Z = Domin_0 (n,(m + 1));
set W = Choose (n,m,1,0);
A1:
( card (Choose (n,(m + 1),1,0)) = (card n) choose (m + 1) & card n = n )
by CARD_1:def 5, CARD_FIN:18;
card ((Choose (n,(m + 1),1,0)) \ (Domin_0 (n,(m + 1)))) = (card (Choose (n,(m + 1),1,0))) - (card (Domin_0 (n,(m + 1))))
by Th25, CARD_2:63;
then A2:
card (Domin_0 (n,(m + 1))) = (card (Choose (n,(m + 1),1,0))) - (card ((Choose (n,(m + 1),1,0)) \ (Domin_0 (n,(m + 1)))))
;
assume
2 * (m + 1) <= n
; card (Domin_0 (n,(m + 1))) = (n choose (m + 1)) - (n choose m)
then
card (Domin_0 (n,(m + 1))) = (card (Choose (n,(m + 1),1,0))) - (card (Choose (n,m,1,0)))
by A2, Th31;
hence
card (Domin_0 (n,(m + 1))) = (n choose (m + 1)) - (n choose m)
by A1, CARD_FIN:18; verum