let x, y be set ; for Ch, F being Function st x in Ch " {y} holds
(Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x) = Intersection (F,Ch,y)
let Ch, F be Function; ( x in Ch " {y} implies (Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x) = Intersection (F,Ch,y) )
set d = (dom Ch) \ {x};
set Chd = Ch | ((dom Ch) \ {x});
set I1 = Intersection (F,Ch,y);
set I2 = Intersection (F,(Ch | ((dom Ch) \ {x})),y);
assume
x in Ch " {y}
; (Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x) = Intersection (F,Ch,y)
then A1:
Intersection (F,Ch,y) c= F . x
by Th33;
A2:
(Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x) c= Intersection (F,Ch,y)
proof
let z be
set ;
TARSKI:def 3 ( not z in (Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x) or z in Intersection (F,Ch,y) )
assume A3:
z in (Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x)
;
z in Intersection (F,Ch,y)
now let x1 be
set ;
( x1 in dom Ch & Ch . x1 = y implies z in F . b1 )assume that A4:
x1 in dom Ch
and A5:
Ch . x1 = y
;
z in F . b1 end;
hence
z in Intersection (
F,
Ch,
y)
by A3, Def2;
verum
end;
Intersection (F,Ch,y) c= Intersection (F,(Ch | ((dom Ch) \ {x})),y)
by Th29;
then
Intersection (F,Ch,y) c= (Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x)
by A1, XBOOLE_1:19;
hence
(Intersection (F,(Ch | ((dom Ch) \ {x})),y)) /\ (F . x) = Intersection (F,Ch,y)
by A2, XBOOLE_0:def 10; verum