consider x being Element of X;
A1:
( X \ {x}, card (X \ {x}) are_equipotent & {x},{(card (X \ {x}))} are_equipotent )
by CARD_1:48, CARD_1:def 5;
A2:
succ (card (X \ {x})) = (card (X \ {x})) \/ {(card (X \ {x}))}
by ORDINAL1:def 1;
not card (X \ {x}) in card (X \ {x})
;
then A3:
{(card (X \ {x}))} misses card (X \ {x})
by ZFMISC_1:56;
( {x} misses X \ {x} & X = (X \ {x}) \/ {x} )
by Lm1, XBOOLE_1:79;
then consider r being Order of X such that
A4:
r well_orders X
and
A5:
order_type_of r = succ (card (X \ {x}))
by A1, A3, A2, Th7, CARD_1:58;
take
r
; ( r is upper-bounded & r is well-ordering )
A6:
field r = X
by ORDERS_1:100;
then
r is well-ordering
by A4, WELLORD1:8;
then
r, RelIncl (order_type_of r) are_isomorphic
by WELLORD2:def 2;
then
RelIncl (order_type_of r),r are_isomorphic
by WELLORD1:50;
then consider f being Function such that
A7:
f is_isomorphism_of RelIncl (order_type_of r),r
by WELLORD1:def 8;
A8:
f is one-to-one
by A7, WELLORD1:def 7;
A9:
rng f = X
by A6, A7, WELLORD1:def 7;
field (RelIncl (order_type_of r)) = order_type_of r
by WELLORD2:def 1;
then A10:
dom f = order_type_of r
by A7, WELLORD1:def 7;
thus
r is upper-bounded
r is well-ordering proof
take a =
f . (card (X \ {x}));
YELLOW21:def 9 for y being set st y in field r holds
[y,a] in r
let y be
set ;
( y in field r implies [y,a] in r )
A11:
card (X \ {x}) in order_type_of r
by A2, A5, SETWISEO:6;
assume A12:
y in field r
;
[y,a] in r
then A13:
(f " ) . y in order_type_of r
by A6, A8, A10, A9, FUNCT_1:54;
then reconsider b =
(f " ) . y as
Ordinal ;
(
(f " ) . y in card (X \ {x}) or
(f " ) . y = card (X \ {x}) )
by A2, A5, A13, SETWISEO:6;
then
b c= card (X \ {x})
by ORDINAL1:def 2;
then
[b,(card (X \ {x}))] in RelIncl (order_type_of r)
by A13, A11, WELLORD2:def 1;
then
[(f . b),a] in r
by A7, WELLORD1:def 7;
hence
[y,a] in r
by A6, A8, A9, A12, FUNCT_1:57;
verum
end;
thus
r is well-ordering
by A4, A6, WELLORD1:8; verum