let x, y be Subset of L; :: thesis: ( ( for c being Element of L holds ( c in x iff ( a <= c & c <= b ) ) ) & ( for c being Element of L holds ( c in y iff ( a <= c & c <= b ) ) ) implies x = y ) assume that A2:
for c being Element of L holds ( c in x iff ( a <= c & c <= b ) )
and A3:
for c being Element of L holds ( c in y iff ( a <= c & c <= b ) )
; :: thesis: x = y