let f be Function of R^1 ,R^1 ; ( f is open iff for p being Point of R^1
for r being real positive number ex s being real positive number st ].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[ )
thus
( f is open implies for p being Point of R^1
for r being real positive number ex s being real positive number st ].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[ )
( ( for p being Point of R^1
for r being real positive number ex s being real positive number st ].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[ ) implies f is open )proof
assume A1:
f is
open
;
for p being Point of R^1
for r being real positive number ex s being real positive number st ].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[
let p be
Point of
R^1 ;
for r being real positive number ex s being real positive number st ].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[let r be
real positive number ;
ex s being real positive number st ].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[
reconsider p1 =
p,
q1 =
f . p as
Point of
RealSpace ;
consider s being
real positive number such that A2:
Ball q1,
s c= f .: (Ball p1,r)
by A1, Th6;
(
r in REAL &
s in REAL )
by XREAL_0:def 1;
then
(
].(p - r),(p + r).[ = Ball p1,
r &
].((f . p) - s),((f . p) + s).[ = Ball q1,
s )
by FRECHET:7;
hence
ex
s being
real positive number st
].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[
by A2;
verum
end;
assume A3:
for p being Point of R^1
for r being real positive number ex s being real positive number st ].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[
; f is open
for p, q being Point of RealSpace
for r being real positive number st q = f . p holds
ex s being real positive number st Ball q,s c= f .: (Ball p,r)
proof
let p,
q be
Point of
RealSpace ;
for r being real positive number st q = f . p holds
ex s being real positive number st Ball q,s c= f .: (Ball p,r)let r be
real positive number ;
( q = f . p implies ex s being real positive number st Ball q,s c= f .: (Ball p,r) )
assume A4:
q = f . p
;
ex s being real positive number st Ball q,s c= f .: (Ball p,r)
consider s being
real positive number such that A5:
].((f . p) - s),((f . p) + s).[ c= f .: ].(p - r),(p + r).[
by A3;
(
r in REAL &
s in REAL )
by XREAL_0:def 1;
then
(
].(p - r),(p + r).[ = Ball p,
r &
].((f . p) - s),((f . p) + s).[ = Ball q,
s )
by A4, FRECHET:7;
hence
ex
s being
real positive number st
Ball q,
s c= f .: (Ball p,r)
by A5;
verum
end;
hence
f is open
by Th6; verum