deffunc H1( set ) -> set = ($1 `1 ) \/ ($1 `2 );
let T be set ; for F, G being Subset-Family of T holds card (UNION F,G) c= card [:F,G:]
let F, G be Subset-Family of T; card (UNION F,G) c= card [:F,G:]
set XX = [:F,G:];
set IN = { H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] } ;
set A = [:(bool T),(bool T):];
set AL = F;
set BL = G;
set C = UNION F,G;
A1:
{ H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] } = UNION F,G
proof
thus
{ H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] } c= UNION F,
G
XBOOLE_0:def 10 UNION F,G c= { H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] } proof
let a be
set ;
TARSKI:def 3 ( not a in { H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] } or a in UNION F,G )
assume
a in { H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] }
;
a in UNION F,G
then consider X being
Element of
[:(bool T),(bool T):] such that A2:
a = H1(
X)
and A3:
X in [:F,G:]
;
(
X `1 in F &
X `2 in G )
by A3, MCART_1:10;
hence
a in UNION F,
G
by A2, SETFAM_1:def 4;
verum
end;
let a be
set ;
TARSKI:def 3 ( not a in UNION F,G or a in { H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] } )
assume
a in UNION F,
G
;
a in { H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] }
then consider X,
Y being
set such that A4:
(
X in F &
Y in G )
and A5:
a = X \/ Y
by SETFAM_1:def 4;
reconsider X =
X,
Y =
Y as
Subset of
T by A4;
set XY =
[X,Y];
A6:
(
[X,Y] `1 = X &
[X,Y] `2 = Y )
by MCART_1:7;
[X,Y] in [:F,G:]
by A4, ZFMISC_1:106;
hence
a in { H1(X) where X is Element of [:(bool T),(bool T):] : X in [:F,G:] }
by A5, A6;
verum
end;
card { H1(w) where w is Element of [:(bool T),(bool T):] : w in [:F,G:] } c= card [:F,G:]
from TREES_2:sch 2();
hence
card (UNION F,G) c= card [:F,G:]
by A1; verum