thus
exp_R " is_differentiable_on dom (exp_R " )
by Th16, FDIFF_2:45; for x being real number st x in dom (exp_R " ) holds
diff (exp_R " ),x = 1 / x
let x be real number ; ( x in dom (exp_R " ) implies diff (exp_R " ),x = 1 / x )
assume A1:
x in dom (exp_R " )
; diff (exp_R " ),x = 1 / x
A2:
x in rng exp_R
by A1, FUNCT_1:55;
diff exp_R ,((exp_R " ) . x) =
exp_R . ((exp_R " ) . x)
by Th16
.=
x
by A2, FUNCT_1:57
;
hence
diff (exp_R " ),x = 1 / x
by A1, Th16, FDIFF_2:45; verum