let b, a be real number ; ( b <= 0 & a <= b implies a * (sqrt (1 + (b ^2 ))) <= b * (sqrt (1 + (a ^2 ))) )
assume that
A1:
b <= 0
and
A2:
a <= b
; a * (sqrt (1 + (b ^2 ))) <= b * (sqrt (1 + (a ^2 )))
A3:
(- a) * (sqrt (1 + (b ^2 ))) = sqrt (((- a) ^2 ) * (1 + (b ^2 )))
by A1, A2, Th124;
( a < b or a = b )
by A2, XXREAL_0:1;
then
( b ^2 < a ^2 or a = b )
by A1, Th114;
then A4:
((b ^2 ) * 1) + ((b ^2 ) * (a ^2 )) <= ((a ^2 ) * 1) + ((a ^2 ) * (b ^2 ))
by XREAL_1:9;
A5:
b ^2 >= 0
by XREAL_1:65;
A6:
a ^2 >= 0
by XREAL_1:65;
then
(- b) * (sqrt (1 + (a ^2 ))) = sqrt (((- b) ^2 ) * (1 + (a ^2 )))
by A1, Th124;
then
- (a * (sqrt (1 + (b ^2 )))) >= - (b * (sqrt (1 + (a ^2 ))))
by A6, A3, A4, A5, Th94;
hence
a * (sqrt (1 + (b ^2 ))) <= b * (sqrt (1 + (a ^2 )))
by XREAL_1:26; verum