for th being real number st th in dom (tan | [.0 ,1.]) holds
tan | [.0 ,1.] is_continuous_in th
proof
let th be
real number ;
( th in dom (tan | [.0 ,1.]) implies tan | [.0 ,1.] is_continuous_in th )
assume A2:
th in dom (tan | [.0 ,1.])
;
tan | [.0 ,1.] is_continuous_in th
then A3:
th in [.0 ,1.]
by RELAT_1:86;
dom sin = REAL
by FUNCT_2:def 1;
then A5:
th in dom sin
by XREAL_0:def 1;
A6:
th in [#] REAL
by XREAL_0:def 1;
then
sin is_differentiable_in th
by Th73, FDIFF_1:16;
then A8:
sin is_continuous_in th
by FDIFF_1:32;
cos is_differentiable_in th
by A6, Th72, FDIFF_1:16;
then A10:
cos is_continuous_in th
by FDIFF_1:32;
cos . th <> 0
by A3, Th74;
then A12:
tan is_continuous_in th
by A5, A8, A10, FCONT_1:11;
now let rseq be
Real_Sequence;
( rng rseq c= dom (tan | [.0 ,1.]) & rseq is convergent & lim rseq = th implies ( (tan | [.0 ,1.]) /* rseq is convergent & (tan | [.0 ,1.]) . th = lim ((tan | [.0 ,1.]) /* rseq) ) )assume that A14:
rng rseq c= dom (tan | [.0 ,1.])
and A15:
(
rseq is
convergent &
lim rseq = th )
;
( (tan | [.0 ,1.]) /* rseq is convergent & (tan | [.0 ,1.]) . th = lim ((tan | [.0 ,1.]) /* rseq) )A16:
rng rseq c= dom tan
by A14, Lm15, Th75, XBOOLE_1:1;
then A17:
tan . th = lim (tan /* rseq)
by A12, A15, FCONT_1:def 1;
now let k1 be
Element of
NAT ;
((tan | [.0 ,1.]) /* rseq) . k1 = (tan /* rseq) . k1
dom rseq = NAT
by SEQ_1:3;
then
rseq . k1 in rng rseq
by FUNCT_1:def 5;
then A21:
(tan | [.0 ,1.]) . (rseq . k1) = tan . (rseq . k1)
by A14, Lm15;
(tan | [.0 ,1.]) . (rseq . k1) = ((tan | [.0 ,1.]) /* rseq) . k1
by A14, FUNCT_2:185;
hence
((tan | [.0 ,1.]) /* rseq) . k1 = (tan /* rseq) . k1
by A14, A21, Lm15, Th75, FUNCT_2:185, XBOOLE_1:1;
verum end; then
(tan | [.0 ,1.]) /* rseq = tan /* rseq
by FUNCT_2:113;
hence
(
(tan | [.0 ,1.]) /* rseq is
convergent &
(tan | [.0 ,1.]) . th = lim ((tan | [.0 ,1.]) /* rseq) )
by A2, A12, A15, A16, A17, Lm15, FCONT_1:def 1;
verum end;
hence
tan | [.0 ,1.] is_continuous_in th
by FCONT_1:def 1;
verum
end;
hence
tan | [.0 ,1.] is continuous
by FCONT_1:def 2; verum