let D be non empty set ; for e, d being Element of D
for F being BinOp of D
for p being FinSequence of D st F . e,d = e holds
F [:] ([#] p,e),d = [#] (F [:] p,d),e
let e, d be Element of D; for F being BinOp of D
for p being FinSequence of D st F . e,d = e holds
F [:] ([#] p,e),d = [#] (F [:] p,d),e
let F be BinOp of D; for p being FinSequence of D st F . e,d = e holds
F [:] ([#] p,e),d = [#] (F [:] p,d),e
let p be FinSequence of D; ( F . e,d = e implies F [:] ([#] p,e),d = [#] (F [:] p,d),e )
assume A1:
F . e,d = e
; F [:] ([#] p,e),d = [#] (F [:] p,d),e
now let i be
Element of
NAT ;
(F [:] ([#] p,e),d) . i = ([#] (F [:] p,d),e) . iA2:
dom p = Seg (len p)
by FINSEQ_1:def 3;
A3:
(
len (F [:] p,d) = len p &
dom (F [:] p,d) = Seg (len (F [:] p,d)) )
by FINSEQ_1:def 3, FINSEQ_2:98;
now per cases
( i in dom p or not i in dom p )
;
suppose A4:
i in dom p
;
F . (([#] p,e) . i),d = ([#] (F [:] p,d),e) . ihence F . (([#] p,e) . i),
d =
F . (p . i),
d
by Th22
.=
(F [:] p,d) . i
by A3, A2, A4, FUNCOP_1:35
.=
([#] (F [:] p,d),e) . i
by A3, A2, A4, Th22
;
verum end; end; end; hence
(F [:] ([#] p,e),d) . i = ([#] (F [:] p,d),e) . i
by FUNCOP_1:60;
verum end;
hence
F [:] ([#] p,e),d = [#] (F [:] p,d),e
by FUNCT_2:113; verum