let SAS be Semi_Affine_Space; for a, o, b being Element of SAS st opposite a,o = opposite b,o holds
a = b
let a, o, b be Element of SAS; ( opposite a,o = opposite b,o implies a = b )
assume A1:
opposite a,o = opposite b,o
; a = b
congr a,o,o, opposite a,o
by Th106;
then A2:
congr opposite a,o,o,o,a
by Th89;
congr b,o,o, opposite b,o
by Th106;
then
congr opposite a,o,o,o,b
by A1, Th89;
hence
a = b
by A2, Th81; verum