thus
( ( for a being set holds P1[a] ) implies for a being set holds P2[a] )
( ( for a being set holds P2[a] ) implies for a being set holds P1[a] )proof
assume A2:
for
a being
set holds
P1[
a]
;
for a being set holds P2[a]
now let a be
set ;
P2[a]
(
P1[
a] iff
P2[
a] )
by A1;
hence
P2[
a]
by A2;
verum end;
hence
for
a being
set holds
P2[
a]
;
verum
end;
assume A3:
for a being set holds P2[a]
; for a being set holds P1[a]
now let a be
set ;
P1[a]
(
P1[
a] iff
P2[
a] )
by A1;
hence
P1[
a]
by A3;
verum end;
hence
for a being set holds P1[a]
; verum