let z, A, B, C, D be set ; ( z in [:A,B,C,D:] implies z = [(z `1_4 ),(z `2_4 ),(z `3_4 ),(z `4_4 )] )
assume A1:
z in [:A,B,C,D:]
; z = [(z `1_4 ),(z `2_4 ),(z `3_4 ),(z `4_4 )]
then A2:
( not C is empty & not D is empty )
by MCART_1:55;
( not A is empty & not B is empty )
by A1, MCART_1:55;
then
ex a being Element of A ex b being Element of B ex c being Element of C ex d being Element of D st z = [a,b,c,d]
by A1, A2, DOMAIN_1:31;
hence
z = [(z `1_4 ),(z `2_4 ),(z `3_4 ),(z `4_4 )]
by Th4; verum