let X, x, y, z be set ; ( [x,y] in [:NAT ,{X}:] & [x,z] in [:NAT ,{X}:] implies y = z )
assume that
A1:
[x,y] in [:NAT ,{X}:]
and
A2:
[x,z] in [:NAT ,{X}:]
; y = z
y in {X}
by A1, ZFMISC_1:106;
then A3:
y = X
by TARSKI:def 1;
z in {X}
by A2, ZFMISC_1:106;
hence
y = z
by A3, TARSKI:def 1; verum