let L be Field; for i, j being Integer
for x being Element of L st x <> 0. L holds
(pow x,i) * (pow x,j) = pow x,(i + j)
let i, j be Integer; for x being Element of L st x <> 0. L holds
(pow x,i) * (pow x,j) = pow x,(i + j)
let x be Element of L; ( x <> 0. L implies (pow x,i) * (pow x,j) = pow x,(i + j) )
defpred S1[ Integer] means for i being Integer holds pow x,(i + $1) = (pow x,i) * (pow x,$1);
assume A1:
x <> 0. L
; (pow x,i) * (pow x,j) = pow x,(i + j)
A2:
for j being Integer st S1[j] holds
( S1[j - 1] & S1[j + 1] )
proof
let j be
Integer;
( S1[j] implies ( S1[j - 1] & S1[j + 1] ) )
assume A3:
for
i being
Integer holds
pow x,
(i + j) = (pow x,i) * (pow x,j)
;
( S1[j - 1] & S1[j + 1] )
thus
for
i being
Integer holds
pow x,
(i + (j - 1)) = (pow x,i) * (pow x,(j - 1))
S1[j + 1]proof
let i be
Integer;
pow x,(i + (j - 1)) = (pow x,i) * (pow x,(j - 1))
thus pow x,
(i + (j - 1)) =
pow x,
((i - 1) + j)
.=
(pow x,(i - 1)) * (pow x,j)
by A3
.=
((pow x,i) * (pow x,(- 1))) * (pow x,j)
by A1, Th20
.=
(pow x,i) * ((pow x,(- 1)) * (pow x,j))
by GROUP_1:def 4
.=
(pow x,i) * (pow x,(j + (- 1)))
by A3
.=
(pow x,i) * (pow x,(j - 1))
;
verum
end;
let i be
Integer;
pow x,(i + (j + 1)) = (pow x,i) * (pow x,(j + 1))
thus pow x,
(i + (j + 1)) =
pow x,
((i + 1) + j)
.=
(pow x,(i + 1)) * (pow x,j)
by A3
.=
((pow x,i) * (pow x,1)) * (pow x,j)
by A1, Th19
.=
(pow x,i) * ((pow x,1) * (pow x,j))
by GROUP_1:def 4
.=
(pow x,i) * (pow x,(j + 1))
by A3
;
verum
end;
A4:
S1[ 0 ]
for j being Integer holds S1[j]
from INT_1:sch 4(A4, A2);
hence
(pow x,i) * (pow x,j) = pow x,(i + j)
; verum