let F be Field; for S being OrtSp of F
for b, a, x, y being Element of S st not a _|_ holds
( PProJ a,b,x,y = 0. F iff x _|_ )
let S be OrtSp of F; for b, a, x, y being Element of S st not a _|_ holds
( PProJ a,b,x,y = 0. F iff x _|_ )
let b, a, x, y be Element of S; ( not a _|_ implies ( PProJ a,b,x,y = 0. F iff x _|_ ) )
set 0F = 0. F;
assume A1:
not a _|_
; ( PProJ a,b,x,y = 0. F iff x _|_ )
then A2:
a <> 0. S
by Th11, Th12;
A3:
( PProJ a,b,x,y = 0. F implies x _|_ )
proof
assume A4:
PProJ a,
b,
x,
y = 0. F
;
x _|_
A5:
now given p being
Element of
S such that A6:
not
a _|_
and A7:
not
x _|_
;
x _|_
((ProJ a,b,p) * (ProJ p,a,x)) * (ProJ x,p,y) = 0. F
by A1, A4, A6, A7, Def7;
then
(
(ProJ a,b,p) * (ProJ p,a,x) = 0. F or
ProJ x,
p,
y = 0. F )
by VECTSP_1:44;
then
(
ProJ a,
b,
p = 0. F or
ProJ p,
a,
x = 0. F or
ProJ x,
p,
y = 0. F )
by VECTSP_1:44;
hence
x _|_
by A1, A6, A7, A8, Th33;
verum end;
hence
x _|_
by A5;
verum
end;
( x _|_ implies PProJ a,b,x,y = 0. F )
proof
assume A11:
x _|_
;
PProJ a,b,x,y = 0. F
A12:
now assume
x <> 0. S
;
PProJ a,b,x,y = 0. Fthen
ex
p being
Element of
S st
( not
a _|_ & not
x _|_ & not
a _|_ & not
x _|_ )
by A2, Def2;
then consider p being
Element of
S such that A13:
not
a _|_
and A14:
not
x _|_
;
ProJ x,
p,
y = 0. F
by A11, A14, Th33;
then
((ProJ a,b,p) * (ProJ p,a,x)) * (ProJ x,p,y) = 0. F
by VECTSP_1:39;
hence
PProJ a,
b,
x,
y = 0. F
by A1, A13, A14, Def7;
verum end;
hence
PProJ a,
b,
x,
y = 0. F
by A12;
verum
end;
hence
( PProJ a,b,x,y = 0. F iff x _|_ )
by A3; verum