let F be Field; :: thesis: for S being OrtSp of F
for b, a, x, y being Element of S st not a _|_ holds
( PProJ a,b,x,y = 0. F iff x _|_ )

let S be OrtSp of F; :: thesis: for b, a, x, y being Element of S st not a _|_ holds
( PProJ a,b,x,y = 0. F iff x _|_ )

let b, a, x, y be Element of S; :: thesis: ( not a _|_ implies ( PProJ a,b,x,y = 0. F iff x _|_ ) )
set 0F = 0. F;
assume A1: not a _|_ ; :: thesis: ( PProJ a,b,x,y = 0. F iff x _|_ )
then A2: a <> 0. S by Th11, Th12;
A3: ( PProJ a,b,x,y = 0. F implies x _|_ )
proof
assume A4: PProJ a,b,x,y = 0. F ; :: thesis: x _|_
A5: now
given p being Element of S such that A6: not a _|_ and
A7: not x _|_ ; :: thesis: x _|_
A8: now
assume A9: ProJ p,a,x = 0. F ; :: thesis: contradiction
not p _|_ by A6, Th12;
then p _|_ by A9, Th33;
hence contradiction by A7, Th12; :: thesis: verum
end;
((ProJ a,b,p) * (ProJ p,a,x)) * (ProJ x,p,y) = 0. F by A1, A4, A6, A7, Def7;
then ( (ProJ a,b,p) * (ProJ p,a,x) = 0. F or ProJ x,p,y = 0. F ) by VECTSP_1:44;
then ( ProJ a,b,p = 0. F or ProJ p,a,x = 0. F or ProJ x,p,y = 0. F ) by VECTSP_1:44;
hence x _|_ by A1, A6, A7, A8, Th33; :: thesis: verum
end;
now
assume A10: for p being Element of S holds
( a _|_ or x _|_ ) ; :: thesis: x _|_
x = 0. S
proof
assume not x = 0. S ; :: thesis: contradiction
then ex p being Element of S st
( not a _|_ & not x _|_ & not a _|_ & not x _|_ ) by A2, Def2;
hence contradiction by A10; :: thesis: verum
end;
hence x _|_ by Th11, Th12; :: thesis: verum
end;
hence x _|_ by A5; :: thesis: verum
end;
( x _|_ implies PProJ a,b,x,y = 0. F )
proof
assume A11: x _|_ ; :: thesis: PProJ a,b,x,y = 0. F
A12: now
assume x <> 0. S ; :: thesis: PProJ a,b,x,y = 0. F
then ex p being Element of S st
( not a _|_ & not x _|_ & not a _|_ & not x _|_ ) by A2, Def2;
then consider p being Element of S such that
A13: not a _|_ and
A14: not x _|_ ;
ProJ x,p,y = 0. F by A11, A14, Th33;
then ((ProJ a,b,p) * (ProJ p,a,x)) * (ProJ x,p,y) = 0. F by VECTSP_1:39;
hence PProJ a,b,x,y = 0. F by A1, A13, A14, Def7; :: thesis: verum
end;
now
assume x = 0. S ; :: thesis: PProJ a,b,x,y = 0. F
then for p being Element of S holds
( a _|_ or x _|_ ) by Th11, Th12;
hence PProJ a,b,x,y = 0. F by A1, Def7; :: thesis: verum
end;
hence PProJ a,b,x,y = 0. F by A12; :: thesis: verum
end;
hence ( PProJ a,b,x,y = 0. F iff x _|_ ) by A3; :: thesis: verum