let K, L, e be real number ; ( 0 < K & K < 1 & 0 < e implies ex n being Element of NAT st abs (L * (K to_power n)) < e )
assume that
A1:
( 0 < K & K < 1 )
and
A2:
0 < e
; ex n being Element of NAT st abs (L * (K to_power n)) < e
deffunc H1( Element of NAT ) -> set = K to_power ($1 + 1);
consider rseq being Real_Sequence such that
A3:
for n being Element of NAT holds rseq . n = H1(n)
from SEQ_1:sch 1();
A4:
L (#) rseq is convergent
by A1, A3, SEQ_2:21, SERIES_1:1;
A5:
lim rseq = 0
by A1, A3, SERIES_1:1;
lim (L (#) rseq) =
L * (lim rseq)
by A1, A3, SEQ_2:22, SERIES_1:1
.=
0
by A5
;
then consider n being Element of NAT such that
A6:
for m being Element of NAT st n <= m holds
abs (((L (#) rseq) . m) - 0 ) < e
by A2, A4, SEQ_2:def 7;
abs (((L (#) rseq) . n) - 0 ) < e
by A6;
then
abs (L * (rseq . n)) < e
by SEQ_1:13;
then
abs (L * (K to_power (n + 1))) < e
by A3;
hence
ex n being Element of NAT st abs (L * (K to_power n)) < e
; verum