let n be Nat; ( not n <= 5 or n = 0 or n = 1 or n = 2 or n = 3 or n = 4 or n = 5 )
assume
n <= 5
; ( n = 0 or n = 1 or n = 2 or n = 3 or n = 4 or n = 5 )
then
n <= 4 + 1
;
hence
( n = 0 or n = 1 or n = 2 or n = 3 or n = 4 or n = 5 )
by Th8, Th29; verum