let S be non empty set ; for R being total Relation of S,S
for BASSIGN being non empty Subset of (ModelSP S)
for f being Assign of (BASSModel R,BASSIGN)
for G1, G2 being Subset of S st G1 c= G2 holds
SigFaxTau f,G1,R,BASSIGN c= SigFaxTau f,G2,R,BASSIGN
let R be total Relation of S,S; for BASSIGN being non empty Subset of (ModelSP S)
for f being Assign of (BASSModel R,BASSIGN)
for G1, G2 being Subset of S st G1 c= G2 holds
SigFaxTau f,G1,R,BASSIGN c= SigFaxTau f,G2,R,BASSIGN
let BASSIGN be non empty Subset of (ModelSP S); for f being Assign of (BASSModel R,BASSIGN)
for G1, G2 being Subset of S st G1 c= G2 holds
SigFaxTau f,G1,R,BASSIGN c= SigFaxTau f,G2,R,BASSIGN
let f be Assign of (BASSModel R,BASSIGN); for G1, G2 being Subset of S st G1 c= G2 holds
SigFaxTau f,G1,R,BASSIGN c= SigFaxTau f,G2,R,BASSIGN
let G1, G2 be Subset of S; ( G1 c= G2 implies SigFaxTau f,G1,R,BASSIGN c= SigFaxTau f,G2,R,BASSIGN )
assume
G1 c= G2
; SigFaxTau f,G1,R,BASSIGN c= SigFaxTau f,G2,R,BASSIGN
then
for s being Element of S st s |= Tau G1,R,BASSIGN holds
s |= Tau G2,R,BASSIGN
by Th34;
then
for s being Element of S st s |= Fax f,(Tau G1,R,BASSIGN) holds
s |= Fax f,(Tau G2,R,BASSIGN)
by Th36;
hence
SigFaxTau f,G1,R,BASSIGN c= SigFaxTau f,G2,R,BASSIGN
by Th35; verum