defpred S1[ Element of S, Element of S, Element of S] means w . $1,$3 = w . $3,$2;
A5:
for a, b, c, c9 being Element of S st S1[a,b,c] & S1[a,b,c9] holds
c = c9
proof
let a,
b,
c,
c9 be
Element of
S;
( S1[a,b,c] & S1[a,b,c9] implies c = c9 )
assume A6:
(
S1[
a,
b,
c] &
S1[
a,
b,
c9] )
;
c = c9
w . c,
c9 =
(w . c,a) + (w . a,c9)
by A1, Def3
.=
(w . c9,b) + (w . b,c)
by A1, A6, Th7
.=
w . c9,
c
by A1, Def3
.=
- (w . c,c9)
by A1, Th6
;
then
w . c,
c9 = 0. G
by Th19;
hence
c = c9
by A1, Th5;
verum
end;
let f, g be BinOp of S; ( ( for a, b being Element of S holds w . a,(f . a,b) = w . (f . a,b),b ) & ( for a, b being Element of S holds w . a,(g . a,b) = w . (g . a,b),b ) implies f = g )
assume A7:
( ( for a, b being Element of S holds w . a,(f . a,b) = w . (f . a,b),b ) & ( for a, b being Element of S holds w . a,(g . a,b) = w . (g . a,b),b ) )
; f = g
for a, b being Element of S holds f . a,b = g . a,b
proof
let a,
b be
Element of
S;
f . a,b = g . a,b
(
w . a,
(f . a,b) = w . (f . a,b),
b &
w . a,
(g . a,b) = w . (g . a,b),
b )
by A7;
hence
f . a,
b = g . a,
b
by A5;
verum
end;
hence
f = g
by BINOP_1:2; verum