let i be Nat; for f being FinSequence of NAT st i in Seg (Sum f) holds
( (min f,i) -' 1 = (min f,i) - 1 & Sum (f | ((min f,i) -' 1)) < i )
let f be FinSequence of NAT ; ( i in Seg (Sum f) implies ( (min f,i) -' 1 = (min f,i) - 1 & Sum (f | ((min f,i) -' 1)) < i ) )
set F = min f,i;
assume A1:
i in Seg (Sum f)
; ( (min f,i) -' 1 = (min f,i) - 1 & Sum (f | ((min f,i) -' 1)) < i )
then
min f,i in dom f
by Def1;
then
1 <= min f,i
by FINSEQ_3:27;
hence A2:
(min f,i) -' 1 = (min f,i) - 1
by XREAL_1:235; Sum (f | ((min f,i) -' 1)) < i
assume
Sum (f | ((min f,i) -' 1)) >= i
; contradiction
then
(min f,i) -' 1 >= (min f,i) - 0
by A1, Def1;
hence
contradiction
by A2, XREAL_1:12; verum