let D be non empty set ; for d being Element of D
for M1, M2 being Matrix of D
for M being Matrix of Sum (Len <*M1,M2*>), Sum (Width <*M1,M2*>),D holds
( M = block_diagonal <*M1,M2*>,d iff for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) ) )
let d be Element of D; for M1, M2 being Matrix of D
for M being Matrix of Sum (Len <*M1,M2*>), Sum (Width <*M1,M2*>),D holds
( M = block_diagonal <*M1,M2*>,d iff for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) ) )
let M1, M2 be Matrix of D; for M being Matrix of Sum (Len <*M1,M2*>), Sum (Width <*M1,M2*>),D holds
( M = block_diagonal <*M1,M2*>,d iff for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) ) )
let M be Matrix of Sum (Len <*M1,M2*>), Sum (Width <*M1,M2*>),D; ( M = block_diagonal <*M1,M2*>,d iff for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) ) )
set m1 = <*M1*>;
set m2 = <*M2*>;
set m12 = <*M1,M2*>;
set B = block_diagonal <*M1,M2*>,d;
A1:
Seg (len M) = dom M
by FINSEQ_1:def 3;
A2:
Seg (len M1) = dom M1
by FINSEQ_1:def 3;
A3:
dom M2 = Seg (len M2)
by FINSEQ_1:def 3;
A4:
Sum (Len <*M1,M2*>) = (len M1) + (len M2)
by Th16;
A5:
( Sum (Len <*M1,M2*>) = 0 implies Sum (Width <*M1,M2*>) = 0 )
by Th13;
then A6:
len M = Sum (Len <*M1,M2*>)
by MATRIX13:1;
A7:
width M = Sum (Width <*M1,M2*>)
by A5, MATRIX13:1;
A8:
Sum (Width <*M1,M2*>) = (width M1) + (width M2)
by Th20;
then
width M1 <= width M
by A7, NAT_1:12;
then A9:
Seg (width M1) c= Seg (width M)
by FINSEQ_1:7;
thus
( M = block_diagonal <*M1,M2*>,d implies for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) ) )
( ( for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) ) ) implies M = block_diagonal <*M1,M2*>,d )proof
A10:
dom ((width M2) |-> d) = Seg (width M2)
by FINSEQ_2:144;
A11:
dom ((width M1) |-> d) = Seg (width M1)
by FINSEQ_2:144;
set L2 =
(len M2) |-> d;
set L1 =
(len M1) |-> d;
assume A12:
M = block_diagonal <*M1,M2*>,
d
;
for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) )
let i be
Nat;
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) )
set CM =
Col M,
i;
set CM1 =
Col M1,
i;
A13:
len (Col M,i) = len M
by FINSEQ_1:def 18;
A14:
dom ((len M1) |-> d) = Seg (len M1)
by FINSEQ_2:144;
A15:
dom ((len M2) |-> d) = Seg (len M2)
by FINSEQ_2:144;
A16:
len (Col M1,i) = len M1
by FINSEQ_1:def 18;
then A17:
dom (Col M1,i) = dom M1
by FINSEQ_3:31;
A18:
len ((len M2) |-> d) = len M2
by FINSEQ_1:def 18;
then A19:
dom ((len M2) |-> d) = dom M2
by FINSEQ_3:31;
thus
(
i in Seg (width M1) implies
Col M,
i = (Col M1,i) ^ ((len M2) |-> d) )
( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) )proof
assume A20:
i in Seg (width M1)
;
Col M,i = (Col M1,i) ^ ((len M2) |-> d)
A21:
len ((Col M1,i) ^ ((len M2) |-> d)) = (len (Col M1,i)) + (len ((len M2) |-> d))
by FINSEQ_1:35;
now let j be
Nat;
( 1 <= j & j <= len (Col M,i) implies ((Col M1,i) ^ ((len M2) |-> d)) . j = (Col M,i) . j )assume that A22:
1
<= j
and A23:
j <= len (Col M,i)
;
((Col M1,i) ^ ((len M2) |-> d)) . j = (Col M,i) . j
j in dom M
by A13, A22, A23, FINSEQ_3:27;
then A24:
(Col M,i) . j = (Line M,j) . i
by A9, A20, GOBOARD1:17;
A25:
dom (Line M1,j) = Seg (width M1)
by FINSEQ_2:144;
A26:
j in dom ((Col M1,i) ^ ((len M2) |-> d))
by A6, A4, A13, A16, A18, A21, A22, A23, FINSEQ_3:27;
now per cases
( j in dom (Col M1,i) or ex k being Nat st
( k in dom ((len M2) |-> d) & j = (len (Col M1,i)) + k ) )
by A26, FINSEQ_1:38;
suppose A27:
j in dom (Col M1,i)
;
(Col M,i) . j = ((Col M1,i) ^ ((len M2) |-> d)) . jhence (Col M,i) . j =
((Line M1,j) ^ ((width M2) |-> d)) . i
by A12, A17, A24, Th23
.=
(Line M1,j) . i
by A20, A25, FINSEQ_1:def 7
.=
(Col M1,i) . j
by A17, A20, A27, GOBOARD1:17
.=
((Col M1,i) ^ ((len M2) |-> d)) . j
by A27, FINSEQ_1:def 7
;
verum end; suppose
ex
k being
Nat st
(
k in dom ((len M2) |-> d) &
j = (len (Col M1,i)) + k )
;
(Col M,i) . j = ((Col M1,i) ^ ((len M2) |-> d)) . jthen consider k being
Nat such that A28:
k in dom ((len M2) |-> d)
and A29:
j = (len (Col M1,i)) + k
;
thus (Col M,i) . j =
(((width M1) |-> d) ^ (Line M2,k)) . i
by A12, A16, A19, A24, A28, A29, Th23
.=
((width M1) |-> d) . i
by A11, A20, FINSEQ_1:def 7
.=
d
by A20, FINSEQ_2:71
.=
((len M2) |-> d) . k
by A15, A28, FINSEQ_2:71
.=
((Col M1,i) ^ ((len M2) |-> d)) . j
by A28, A29, FINSEQ_1:def 7
;
verum end; end; end; hence
((Col M1,i) ^ ((len M2) |-> d)) . j = (Col M,i) . j
;
verum end;
hence
Col M,
i = (Col M1,i) ^ ((len M2) |-> d)
by A6, A13, A16, A18, A21, Th16, FINSEQ_1:18;
verum
end;
set CM2 =
Col M2,
i;
set CMi =
Col M,
(i + (width M1));
A30:
len (Col M,(i + (width M1))) = len M
by FINSEQ_1:def 18;
A31:
len (Col M2,i) = len M2
by FINSEQ_1:def 18;
then A32:
dom (Col M2,i) = dom M2
by FINSEQ_3:31;
A33:
len (((len M1) |-> d) ^ (Col M2,i)) = (len ((len M1) |-> d)) + (len (Col M2,i))
by FINSEQ_1:35;
assume A34:
i in Seg (width M2)
;
Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i)
A35:
len ((len M1) |-> d) = len M1
by FINSEQ_1:def 18;
then A36:
dom ((len M1) |-> d) = dom M1
by FINSEQ_3:31;
now A37:
len ((width M1) |-> d) = width M1
by FINSEQ_1:def 18;
let j be
Nat;
( 1 <= j & j <= len (Col M,(i + (width M1))) implies (((len M1) |-> d) ^ (Col M2,i)) . j = (Col M,(i + (width M1))) . j )assume that A38:
1
<= j
and A39:
j <= len (Col M,(i + (width M1)))
;
(((len M1) |-> d) ^ (Col M2,i)) . j = (Col M,(i + (width M1))) . jA40:
j in dom M
by A30, A38, A39, FINSEQ_3:27;
i + (width M1) in Seg (width M)
by A7, A8, A34, FINSEQ_1:81;
then A41:
(Col M,(i + (width M1))) . j = (Line M,j) . (i + (width M1))
by A40, GOBOARD1:17;
A42:
len (Line M1,j) = width M1
by FINSEQ_1:def 18;
A43:
j in dom (((len M1) |-> d) ^ (Col M2,i))
by A6, A4, A30, A31, A35, A33, A38, A39, FINSEQ_3:27;
now per cases
( j in dom ((len M1) |-> d) or ex k being Nat st
( k in dom (Col M2,i) & j = (len ((len M1) |-> d)) + k ) )
by A43, FINSEQ_1:38;
suppose A44:
j in dom ((len M1) |-> d)
;
(Col M,(i + (width M1))) . j = (((len M1) |-> d) ^ (Col M2,i)) . jhence (Col M,(i + (width M1))) . j =
((Line M1,j) ^ ((width M2) |-> d)) . (i + (width M1))
by A12, A36, A41, Th23
.=
((width M2) |-> d) . i
by A10, A34, A42, FINSEQ_1:def 7
.=
d
by A34, FINSEQ_2:71
.=
((len M1) |-> d) . j
by A14, A44, FINSEQ_2:71
.=
(((len M1) |-> d) ^ (Col M2,i)) . j
by A44, FINSEQ_1:def 7
;
verum end; suppose
ex
k being
Nat st
(
k in dom (Col M2,i) &
j = (len ((len M1) |-> d)) + k )
;
(Col M,(i + (width M1))) . j = (((len M1) |-> d) ^ (Col M2,i)) . jthen consider k being
Nat such that A45:
k in dom (Col M2,i)
and A46:
j = (len ((len M1) |-> d)) + k
;
A47:
dom (Line M2,k) = Seg (width M2)
by FINSEQ_2:144;
thus (Col M,(i + (width M1))) . j =
(((width M1) |-> d) ^ (Line M2,k)) . (i + (width M1))
by A12, A35, A32, A41, A45, A46, Th23
.=
(Line M2,k) . i
by A34, A37, A47, FINSEQ_1:def 7
.=
(Col M2,i) . k
by A32, A34, A45, GOBOARD1:17
.=
(((len M1) |-> d) ^ (Col M2,i)) . j
by A45, A46, FINSEQ_1:def 7
;
verum end; end; end; hence
(((len M1) |-> d) ^ (Col M2,i)) . j = (Col M,(i + (width M1))) . j
;
verum end;
hence
Col M,
(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i)
by A6, A30, A31, A35, A33, Th16, FINSEQ_1:18;
verum
end;
assume A48:
for i being Nat holds
( ( i in Seg (width M1) implies Col M,i = (Col M1,i) ^ ((len M2) |-> d) ) & ( i in Seg (width M2) implies Col M,(i + (width M1)) = ((len M1) |-> d) ^ (Col M2,i) ) )
; M = block_diagonal <*M1,M2*>,d
len M1 <= len M
by A6, A4, NAT_1:12;
then A49:
Seg (len M1) c= Seg (len M)
by FINSEQ_1:7;
now set W2 =
(width M2) |-> d;
set W1 =
(width M1) |-> d;
let i be
Nat;
( ( i in dom M1 implies Line M,i = (Line M1,i) ^ ((width M2) |-> d) ) & ( i in dom M2 implies Line M,(i + (len M1)) = ((width M1) |-> d) ^ (Line M2,i) ) )set LM =
Line M,
i;
set LMi =
Line M,
(i + (len M1));
set LM1 =
Line M1,
i;
set LM2 =
Line M2,
i;
A50:
len (Line M,(i + (len M1))) = width M
by FINSEQ_1:def 18;
A51:
len ((width M2) |-> d) = width M2
by FINSEQ_1:def 18;
then A52:
dom ((width M2) |-> d) = Seg (width M2)
by FINSEQ_1:def 3;
A53:
len (Line M,i) = width M
by FINSEQ_1:def 18;
then A54:
dom (Line M,i) = Seg (width M)
by FINSEQ_1:def 3;
A55:
len (Line M1,i) = width M1
by FINSEQ_1:def 18;
then A56:
dom (Line M1,i) = Seg (width M1)
by FINSEQ_1:def 3;
thus
(
i in dom M1 implies
Line M,
i = (Line M1,i) ^ ((width M2) |-> d) )
( i in dom M2 implies Line M,(i + (len M1)) = ((width M1) |-> d) ^ (Line M2,i) )proof
assume A57:
i in dom M1
;
Line M,i = (Line M1,i) ^ ((width M2) |-> d)
A58:
len ((Line M1,i) ^ ((width M2) |-> d)) = (len (Line M1,i)) + (len ((width M2) |-> d))
by FINSEQ_1:35;
now A59:
dom ((len M1) |-> d) = Seg (len M1)
by FINSEQ_2:144;
let j be
Nat;
( 1 <= j & j <= len (Line M,i) implies (Line M,i) . j = ((Line M1,i) ^ ((width M2) |-> d)) . j )assume that A60:
1
<= j
and A61:
j <= len (Line M,i)
;
(Line M,i) . j = ((Line M1,i) ^ ((width M2) |-> d)) . j
j in Seg (width M)
by A54, A60, A61, FINSEQ_3:27;
then A62:
(Line M,i) . j = (Col M,j) . i
by A49, A1, A2, A57, GOBOARD1:17;
A63:
dom (Col M1,j) = Seg (len M1)
by FINSEQ_2:144;
A64:
j in dom ((Line M1,i) ^ ((width M2) |-> d))
by A7, A8, A53, A55, A51, A58, A60, A61, FINSEQ_3:27;
now per cases
( j in dom (Line M1,i) or ex n being Nat st
( n in dom ((width M2) |-> d) & j = (len (Line M1,i)) + n ) )
by A64, FINSEQ_1:38;
suppose A65:
j in dom (Line M1,i)
;
(Line M,i) . j = ((Line M1,i) ^ ((width M2) |-> d)) . jhence (Line M,i) . j =
((Col M1,j) ^ ((len M2) |-> d)) . i
by A48, A56, A62
.=
(Col M1,j) . i
by A2, A57, A63, FINSEQ_1:def 7
.=
(Line M1,i) . j
by A56, A57, A65, GOBOARD1:17
.=
((Line M1,i) ^ ((width M2) |-> d)) . j
by A65, FINSEQ_1:def 7
;
verum end; suppose
ex
n being
Nat st
(
n in dom ((width M2) |-> d) &
j = (len (Line M1,i)) + n )
;
(Line M,i) . j = ((Line M1,i) ^ ((width M2) |-> d)) . jthen consider n being
Nat such that A66:
n in dom ((width M2) |-> d)
and A67:
j = (len (Line M1,i)) + n
;
thus (Line M,i) . j =
(((len M1) |-> d) ^ (Col M2,n)) . i
by A48, A55, A52, A62, A66, A67
.=
((len M1) |-> d) . i
by A2, A57, A59, FINSEQ_1:def 7
.=
d
by A2, A57, FINSEQ_2:71
.=
((width M2) |-> d) . n
by A52, A66, FINSEQ_2:71
.=
((Line M1,i) ^ ((width M2) |-> d)) . j
by A66, A67, FINSEQ_1:def 7
;
verum end; end; end; hence
(Line M,i) . j = ((Line M1,i) ^ ((width M2) |-> d)) . j
;
verum end;
hence
Line M,
i = (Line M1,i) ^ ((width M2) |-> d)
by A7, A53, A55, A51, A58, Th20, FINSEQ_1:18;
verum
end; A68:
len (Line M2,i) = width M2
by FINSEQ_1:def 18;
then A69:
dom (Line M2,i) = Seg (width M2)
by FINSEQ_1:def 3;
A70:
len ((width M1) |-> d) = width M1
by FINSEQ_1:def 18;
then A71:
dom ((width M1) |-> d) = Seg (width M1)
by FINSEQ_1:def 3;
thus
(
i in dom M2 implies
Line M,
(i + (len M1)) = ((width M1) |-> d) ^ (Line M2,i) )
verumproof
assume A72:
i in dom M2
;
Line M,(i + (len M1)) = ((width M1) |-> d) ^ (Line M2,i)
A73:
len (((width M1) |-> d) ^ (Line M2,i)) = (len ((width M1) |-> d)) + (len (Line M2,i))
by FINSEQ_1:35;
now A74:
len ((len M1) |-> d) = len M1
by FINSEQ_1:def 18;
A75:
dom ((len M2) |-> d) = Seg (len M2)
by FINSEQ_2:144;
A76:
dom M2 = Seg (len M2)
by FINSEQ_1:def 3;
let j be
Nat;
( 1 <= j & j <= len (Line M,(i + (len M1))) implies (Line M,(i + (len M1))) . j = (((width M1) |-> d) ^ (Line M2,i)) . j )assume that A77:
1
<= j
and A78:
j <= len (Line M,(i + (len M1)))
;
(Line M,(i + (len M1))) . j = (((width M1) |-> d) ^ (Line M2,i)) . j
j in Seg (width M)
by A53, A50, A54, A77, A78, FINSEQ_3:27;
then A79:
(Line M,(i + (len M1))) . j = (Col M,j) . (i + (len M1))
by A6, A4, A1, A72, A76, FINSEQ_1:81, GOBOARD1:17;
A80:
len (Col M1,j) = len M1
by FINSEQ_1:def 18;
A81:
j in dom (((width M1) |-> d) ^ (Line M2,i))
by A7, A8, A50, A68, A70, A73, A77, A78, FINSEQ_3:27;
now per cases
( j in dom ((width M1) |-> d) or ex n being Nat st
( n in dom (Line M2,i) & j = (len ((width M1) |-> d)) + n ) )
by A81, FINSEQ_1:38;
suppose A82:
j in dom ((width M1) |-> d)
;
(Line M,(i + (len M1))) . j = (((width M1) |-> d) ^ (Line M2,i)) . jhence (Line M,(i + (len M1))) . j =
((Col M1,j) ^ ((len M2) |-> d)) . (i + (len M1))
by A48, A71, A79
.=
((len M2) |-> d) . i
by A3, A72, A80, A75, FINSEQ_1:def 7
.=
d
by A3, A72, FINSEQ_2:71
.=
((width M1) |-> d) . j
by A71, A82, FINSEQ_2:71
.=
(((width M1) |-> d) ^ (Line M2,i)) . j
by A82, FINSEQ_1:def 7
;
verum end; suppose
ex
n being
Nat st
(
n in dom (Line M2,i) &
j = (len ((width M1) |-> d)) + n )
;
(Line M,(i + (len M1))) . j = (((width M1) |-> d) ^ (Line M2,i)) . jthen consider n being
Nat such that A83:
n in dom (Line M2,i)
and A84:
j = (len ((width M1) |-> d)) + n
;
A85:
dom (Col M2,n) = Seg (len M2)
by FINSEQ_2:144;
thus (Line M,(i + (len M1))) . j =
(((len M1) |-> d) ^ (Col M2,n)) . (i + (len M1))
by A48, A70, A69, A79, A83, A84
.=
(Col M2,n) . i
by A3, A72, A74, A85, FINSEQ_1:def 7
.=
(Line M2,i) . n
by A69, A72, A83, GOBOARD1:17
.=
(((width M1) |-> d) ^ (Line M2,i)) . j
by A83, A84, FINSEQ_1:def 7
;
verum end; end; end; hence
(Line M,(i + (len M1))) . j = (((width M1) |-> d) ^ (Line M2,i)) . j
;
verum end;
hence
Line M,
(i + (len M1)) = ((width M1) |-> d) ^ (Line M2,i)
by A7, A50, A68, A70, A73, Th20, FINSEQ_1:18;
verum
end; end;
hence
M = block_diagonal <*M1,M2*>,d
by Th23; verum