let n be Nat; for K being Field
for M1, M2, M3 being Matrix of n,K st M1 is invertible & M2 is invertible & M3 is invertible holds
( (M1 * M2) * M3 is invertible & ((M1 * M2) * M3) ~ = ((M3 ~ ) * (M2 ~ )) * (M1 ~ ) )
let K be Field; for M1, M2, M3 being Matrix of n,K st M1 is invertible & M2 is invertible & M3 is invertible holds
( (M1 * M2) * M3 is invertible & ((M1 * M2) * M3) ~ = ((M3 ~ ) * (M2 ~ )) * (M1 ~ ) )
let M1, M2, M3 be Matrix of n,K; ( M1 is invertible & M2 is invertible & M3 is invertible implies ( (M1 * M2) * M3 is invertible & ((M1 * M2) * M3) ~ = ((M3 ~ ) * (M2 ~ )) * (M1 ~ ) ) )
assume that
A1:
M1 is invertible
and
A2:
M2 is invertible
and
A3:
M3 is invertible
; ( (M1 * M2) * M3 is invertible & ((M1 * M2) * M3) ~ = ((M3 ~ ) * (M2 ~ )) * (M1 ~ ) )
A4:
M1 ~ is_reverse_of M1
by A1, Def4;
A5:
M2 ~ is_reverse_of M2
by A2, Def4;
A6:
len M3 = n
by MATRIX_1:25;
A7:
M3 ~ is_reverse_of M3
by A3, Def4;
A8:
width (M2 ~ ) = n
by MATRIX_1:25;
A9:
width M3 = n
by MATRIX_1:25;
A10:
width (M1 * M2) = n
by MATRIX_1:25;
A11:
len (M1 ~ ) = n
by MATRIX_1:25;
set M5 = ((M3 ~ ) * (M2 ~ )) * (M1 ~ );
set M4 = (M1 * M2) * M3;
A12:
width M2 = n
by MATRIX_1:25;
A13:
( len (M2 * M3) = n & width (((M3 ~ ) * (M2 ~ )) * (M1 ~ )) = n )
by MATRIX_1:25;
A14:
len M2 = n
by MATRIX_1:25;
A15:
( width ((M1 * M2) * M3) = n & len ((M2 ~ ) * (M1 ~ )) = n )
by MATRIX_1:25;
A16:
len (M3 ~ ) = n
by MATRIX_1:25;
A17:
width ((M3 ~ ) * (M2 ~ )) = n
by MATRIX_1:25;
A18:
width (M3 ~ ) = n
by MATRIX_1:25;
A19:
width (M1 ~ ) = n
by MATRIX_1:25;
A20:
len M1 = n
by MATRIX_1:25;
A21:
len (M2 ~ ) = n
by MATRIX_1:25;
A22:
width M1 = n
by MATRIX_1:25;
then A23: (((M3 ~ ) * (M2 ~ )) * (M1 ~ )) * ((M1 * M2) * M3) =
(((M3 ~ ) * (M2 ~ )) * (M1 ~ )) * (M1 * (M2 * M3))
by A12, A14, A6, MATRIX_3:35
.=
((((M3 ~ ) * (M2 ~ )) * (M1 ~ )) * M1) * (M2 * M3)
by A22, A20, A13, MATRIX_3:35
.=
(((M3 ~ ) * (M2 ~ )) * ((M1 ~ ) * M1)) * (M2 * M3)
by A20, A19, A11, A17, MATRIX_3:35
.=
(((M3 ~ ) * (M2 ~ )) * (1. K,n)) * (M2 * M3)
by A4, Def2
.=
((M3 ~ ) * (M2 ~ )) * (M2 * M3)
by MATRIX_3:21
.=
(((M3 ~ ) * (M2 ~ )) * M2) * M3
by A12, A14, A6, A17, MATRIX_3:35
.=
((M3 ~ ) * ((M2 ~ ) * M2)) * M3
by A14, A8, A18, A21, MATRIX_3:35
.=
((M3 ~ ) * (1. K,n)) * M3
by A5, Def2
.=
(M3 ~ ) * M3
by MATRIX_3:21
.=
1. K,n
by A7, Def2
;
((M1 * M2) * M3) * (((M3 ~ ) * (M2 ~ )) * (M1 ~ )) =
((M1 * M2) * M3) * ((M3 ~ ) * ((M2 ~ ) * (M1 ~ )))
by A8, A18, A11, A21, MATRIX_3:35
.=
(((M1 * M2) * M3) * (M3 ~ )) * ((M2 ~ ) * (M1 ~ ))
by A18, A16, A15, MATRIX_3:35
.=
((M1 * M2) * (M3 * (M3 ~ ))) * ((M2 ~ ) * (M1 ~ ))
by A9, A6, A10, A16, MATRIX_3:35
.=
((M1 * M2) * (1. K,n)) * ((M2 ~ ) * (M1 ~ ))
by A7, Def2
.=
(M1 * M2) * ((M2 ~ ) * (M1 ~ ))
by MATRIX_3:21
.=
((M1 * M2) * (M2 ~ )) * (M1 ~ )
by A10, A8, A11, A21, MATRIX_3:35
.=
(M1 * (M2 * (M2 ~ ))) * (M1 ~ )
by A22, A12, A14, A21, MATRIX_3:35
.=
(M1 * (1. K,n)) * (M1 ~ )
by A5, Def2
.=
M1 * (M1 ~ )
by MATRIX_3:21
.=
1. K,n
by A4, Def2
;
then A24:
((M3 ~ ) * (M2 ~ )) * (M1 ~ ) is_reverse_of (M1 * M2) * M3
by A23, Def2;
then
(M1 * M2) * M3 is invertible
by Def3;
hence
( (M1 * M2) * M3 is invertible & ((M1 * M2) * M3) ~ = ((M3 ~ ) * (M2 ~ )) * (M1 ~ ) )
by A24, Def4; verum