let n be Nat; for K being Field
for a being Element of K holds (n,n --> a) @ = n,n --> a
let K be Field; for a being Element of K holds (n,n --> a) @ = n,n --> a
let a be Element of K; (n,n --> a) @ = n,n --> a
len (n,n --> a) = n
by MATRIX_1:25;
then A1:
len ((n,n --> a) @ ) = len (n,n --> a)
by MATRIX_1:25;
A2:
Indices (n,n --> a) = [:(Seg n),(Seg n):]
by MATRIX_1:25;
A3:
for i, j being Nat st [i,j] in Indices ((n,n --> a) @ ) holds
((n,n --> a) @ ) * i,j = (n,n --> a) * i,j
proof
let i,
j be
Nat;
( [i,j] in Indices ((n,n --> a) @ ) implies ((n,n --> a) @ ) * i,j = (n,n --> a) * i,j )
assume
[i,j] in Indices ((n,n --> a) @ )
;
((n,n --> a) @ ) * i,j = (n,n --> a) * i,j
then A4:
[i,j] in Indices (n,n --> a)
by MATRIX_1:27;
then
(
i in Seg n &
j in Seg n )
by A2, ZFMISC_1:106;
then
[j,i] in Indices (n,n --> a)
by A2, ZFMISC_1:106;
then
(
((n,n --> a) @ ) * i,
j = (n,n --> a) * j,
i &
(n,n --> a) * j,
i = a )
by MATRIX_1:def 7, MATRIX_2:1;
hence
((n,n --> a) @ ) * i,
j = (n,n --> a) * i,
j
by A4, MATRIX_2:1;
verum
end;
width (n,n --> a) = n
by MATRIX_1:25;
then
width ((n,n --> a) @ ) = width (n,n --> a)
by MATRIX_1:25;
hence
(n,n --> a) @ = n,n --> a
by A1, A3, MATRIX_1:21; verum