let D be non empty set ; for i being Nat
for A being Matrix of D holds Segm A,((Seg (len A)) \ {i}),(Seg (width A)) = Del A,i
let i be Nat; for A being Matrix of D holds Segm A,((Seg (len A)) \ {i}),(Seg (width A)) = Del A,i
let A be Matrix of D; Segm A,((Seg (len A)) \ {i}),(Seg (width A)) = Del A,i
set SLA = Seg (len A);
set Si = (Seg (len A)) \ {i};
set S = Segm A,((Seg (len A)) \ {i}),(Seg (width A));
A1:
dom A = Seg (len A)
by FINSEQ_1:def 3;
per cases
( not i in dom A or i in dom A )
;
suppose A4:
i in dom A
;
Segm A,((Seg (len A)) \ {i}),(Seg (width A)) = Del A,ithen consider m being
Nat such that A5:
len A = m + 1
and A6:
len (Del A,i) = m
by FINSEQ_3:113;
reconsider m =
m as
Element of
NAT by ORDINAL1:def 13;
card (Seg (len A)) = m + 1
by A5, FINSEQ_1:78;
then A7:
card ((Seg (len A)) \ {i}) = m
by A1, A4, STIRL2_1:65;
A8:
now reconsider A9 =
A as
Matrix of
m + 1,
width A,
D by A5, MATRIX_1:20;
let j be
Nat;
( 1 <= j & j <= m implies (Del A,i) . j = (Segm A,((Seg (len A)) \ {i}),(Seg (width A))) . j )assume that A9:
1
<= j
and A10:
j <= m
;
(Del A,i) . j = (Segm A,((Seg (len A)) \ {i}),(Seg (width A))) . j
j in NAT
by ORDINAL1:def 13;
then A11:
j in Seg m
by A9, A10;
A12:
dom A = Seg (len A)
by FINSEQ_1:def 3;
A13:
Del A,
i = A * (Sgm ((Seg (len A)) \ {i}))
by A1, FINSEQ_3:def 2;
A14:
dom (Del A,i) = Seg m
by A6, FINSEQ_1:def 3;
then A15:
(Sgm ((Seg (len A)) \ {i})) . j in dom A
by A11, A13, FUNCT_1:21;
(Del A,i) . j = A9 . ((Sgm ((Seg (len A)) \ {i})) . j)
by A14, A11, A13, FUNCT_1:22;
hence (Del A,i) . j =
Line A9,
((Sgm ((Seg (len A)) \ {i})) . j)
by A5, A15, A12, MATRIX_2:10
.=
Line (Segm A,((Seg (len A)) \ {i}),(Seg (width A))),
j
by A7, A11, Th48
.=
(Segm A,((Seg (len A)) \ {i}),(Seg (width A))) . j
by A7, A11, MATRIX_2:10
;
verum end;
len (Segm A,((Seg (len A)) \ {i}),(Seg (width A))) = m
by A7, MATRIX_1:def 3;
hence
Segm A,
((Seg (len A)) \ {i}),
(Seg (width A)) = Del A,
i
by A6, A8, FINSEQ_1:18;
verum end; end;